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One Angstrom is equal to.
A. \[{10^8}\,{\text{m}}\]
B. \[{10^{ - 10}}\,{\text{m}}\]
C. \[{10^{ - 8}}\,{\text{m}}\]
D. \[{10^{10}}\,{\text{m}}\]

seo-qna
Last updated date: 23rd Aug 2024
Total views: 414k
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Answer
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Hint:Angstrom is a unit of measurement of very small length. Angstrom unit is used to express the diameter or radius of an atom and also the spacing in atomic lattices.

Complete answer:
We know that Angstrom is a unit of measurement of very small length. We generally use the Angstrom unit to express the diameter or radius of an atom and also the diameter of elementary particles. It is denoted by the symbol \[{A^0}\] which is a letter in Swedish.

We know that the diameter of the atoms have the value close to multiples of \[{10^{ - 10}}\,{\text{m}}\]. Therefore, the unit Angstrom is generally used in physical chemistry.

One Angstrom is equal to \[{10^{ - 10}}\,{\text{m}}\]. Hence,option B is the correct answer.

Additional information:
Angstrom unit is named after the Swedish scientist Anders Jonas Angstrom. He depicted the wavelengths of electromagnetic radiations in the Angstrom unit. The wavelengths of radiations are generally expressed in nanometers (nm) but since nm is just 10 times the \[{A^0}\], we also use \[{A^0}\] to express the wavelength. In crystallography, the distance between planes of atoms is expressed in \[{A^0}\]. We know that for every \[{10^{ - 3}}\,{\text{m}}\] multiple of meters, we have a different unit of measurement. That is,
\[{10^{ - 3}}\,{\text{m}} = 1\,{\text{mm}}\], \[{10^{ - 6}}\,{\text{m}} = 1\,{\text{\mu m}}\], \[{10^{ - 9}}\,{\text{m}} = 1\,{\text{nm}}\] and\[{10^{ - 12}}\,{\text{m}} = 1\,{\text{pm}}\].

Note:Not just \[{A^0}\], but students should remember every derived S.I unit of the distance measurement. When we express a very small unit in terms of\[{A^0}\], it gets easy while doing calculations. Since \[{10^{ - 9}}\,{\text{m}} = 1\,{\text{nm}}\], we can express it as 0.1\[{A^0}\], but the units nm and \[{A^0}\] are used in different ways and we do not correlate them.