One mole of ${C{O_2}}$ contains?
(A). $6.02\times {{10} ^ {23}} $ atoms of oxygen
(B). $6.02\times {{10} ^ {23}} $ atoms of carbon
(C). $18.10\times {{10} ^ {23}} $ molecules of ${C{O_2}}$
(D) $3$g atoms of ${C{O_2}}$
Answer
Verified
403.7k+ views
- Hint: In the question we have to answer that one mole of CO2 contains how many entities just like one dozen bananas contains how many bananas.
Complete step by step answer:
Let’s dive into mole,
We know that one mole is the amount of a substance that contains as many particles or entities as there are in exactly $12$ g of the 12C isotope.
i.e. one mole of any element (or $1$ g atom) = $6.02\times {{10} ^ {23}} $ atoms.
Now, in the question the given compound CO2 there are two oxygen atoms and one carbon atom. Therefore, one mole of CO2 contains one mole of carbon and two moles of oxygen.
$1$ mole of CO2 = $1$ mole of C = $6.02\times {{10} ^ {23}} $ atoms of carbon.
$1$ mole of CO2 = $2$ mole of O = $2\times 6.02\times {{10} ^ {23}} $ = $12.04\times {{10} ^ {23}} $ atoms of oxygen.
But according to definition of mole,
$1$ mole of CO2 = $6.02\times {{10} ^ {23}} $ molecules of CO2
Therefore, options (b) is correct.
Note: Here $6.02\times {{10} ^ {23}} $ is known as Avogadro’s number (NA). It represents us the number of atoms/molecules/entities present in one mole of a substance. The mole concept is a bit confusing for most students , so I recommend that please read it carefully and as many times as you can. Also try to compare it with daily measurements.
Complete step by step answer:
Let’s dive into mole,
We know that one mole is the amount of a substance that contains as many particles or entities as there are in exactly $12$ g of the 12C isotope.
i.e. one mole of any element (or $1$ g atom) = $6.02\times {{10} ^ {23}} $ atoms.
Now, in the question the given compound CO2 there are two oxygen atoms and one carbon atom. Therefore, one mole of CO2 contains one mole of carbon and two moles of oxygen.
$1$ mole of CO2 = $1$ mole of C = $6.02\times {{10} ^ {23}} $ atoms of carbon.
$1$ mole of CO2 = $2$ mole of O = $2\times 6.02\times {{10} ^ {23}} $ = $12.04\times {{10} ^ {23}} $ atoms of oxygen.
But according to definition of mole,
$1$ mole of CO2 = $6.02\times {{10} ^ {23}} $ molecules of CO2
Therefore, options (b) is correct.
Note: Here $6.02\times {{10} ^ {23}} $ is known as Avogadro’s number (NA). It represents us the number of atoms/molecules/entities present in one mole of a substance. The mole concept is a bit confusing for most students , so I recommend that please read it carefully and as many times as you can. Also try to compare it with daily measurements.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success
Master Class 12 English: Engaging Questions & Answers for Success
Master Class 12 Economics: Engaging Questions & Answers for Success
Master Class 12 Chemistry: Engaging Questions & Answers for Success
Master Class 12 Social Science: Engaging Questions & Answers for Success
Class 12 Question and Answer - Your Ultimate Solutions Guide
Trending doubts
10 examples of friction in our daily life
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
State and prove Bernoullis theorem class 11 physics CBSE
Pigmented layer in the eye is called as a Cornea b class 11 biology CBSE
State the laws of reflection of light