VerifiedHint: As we know that oxidation number is the number of electrons that the atom gains or losses during the formation of a chemical bond. It can be positive, negative or zero. We should use the rules to calculate the oxidation number of carbon.
Complete Step By Step Answer:
- There are some rules for calculating the oxidation numbers like:
- Oxidation number of a monatomic ion is equal to the charge on it; the oxidation number of any free element is zero. Halogens have oxidation number = -1. And it is found that the oxidation number of oxygen is -2, but in case of peroxides, it is -1.
- As we know that the molecular mass of carbon, hydrogen and oxygen are 12, 16, 1. Now, let’s calculate the oxidation number of carbon in $ {{C}_{6}}{{H}_{12}}{{O}_{6}} $ :
- Let us take x to be the oxidation number of carbon. So, we can calculate it as:
$ {{C}_{6}}{{H}_{12}}{{O}_{6}} $
$= x\times 6+1\times \left( 12 \right)+6\times \left( -2 \right)$
$= x\times 6+12-12$
$x = 0$
Hence, we can conclude that the correct option is (c), that is the oxidation number of C in $ {{C}_{6}}{{H}_{12}}{{O}_{6}} $ is 0.
So, the correct answer is “Option C”.
Note: As we know that oxidation state is the only charge which shows the negative or positive character of the atom.
- We should not get confused in terms of oxidation and reduction. As in oxidation loss of electrons takes place or we can say gain of oxygen takes place. Whereas, in reduction, gain of electrons takes place or we can say gain of hydrogen takes place.
