Oxymercuration-demercuration reaction \[{\text{Hg(OAC}}{{\text{)}}_{\text{2}}}{\text{/THF - }}{{\text{H}}_{\text{2}}}{\text{O followed by NaB}}{{\text{H}}_{\text{4}}},{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH)}}\]on \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{CH = C}}{{\text{H}}_{\text{2}}}\]produces:
A)\[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CO}}\]
B) \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{CH(OH)C}}{{\text{H}}_3}\]
C) \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{CH(OH)C}}{{\text{H}}_{\text{2}}}{\text{OH}}\]
D) \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{COC}}{{\text{H}}_3}\]
Answer
Verified
451.2k+ views
Hint:Oxymercuration-demarcation reaction is an alternative method of hydration of alkene. Given alkene is an asymmetric alkene. Additions take place according to Markovnikov’s rule. The first step of the reaction is the formation of cyclic mercurinium ions. The second step is the opening of mercurinium ion by the nucleophilic attack of water. Finally, demercuration takes place by reduction with \[{\text{NaB}}{{\text{H}}_{\text{4}}}\] the reagent.
Complete solution:
As we know that Oxymercuration-demercuration reaction is a hydration reaction so the product of the reaction will be alcohol.Hence, Option (A) and (D) are the incorrect answers.
Now we will see the detail mechanism of the Oxymercuration-demercuration reaction.
Step1: Formation of cyclic mercurinium ion: Nucleophilic attack of \[\pi \] electrons of \[{\text{C = C}}\]on electrophilic \[{\text{Hg}}\] and loss of an acetate ion.
Step2: Opening of mercurinium ion by nucleophilic attack of water. Attack of water takes place according to Markovnikov’s rule, that is it attacks on the more substituted carbon atom.
Step3: Deprotonation of oxonium ion by base acetate ion.
Step4: Breaking of \[{\text{C - Hg}}\] bond and formation of \[{\text{C - H}}\] by reduction with\[{\text{NaB}}{{\text{H}}_{\text{4}}}\].
Thus, option (D) is incorrect as the product is not diol.
Thus, the correct options are (B).
Note:Oxymercuration-demercuration reaction involves the transformation of \[{\text{C = C}}\] to \[{\text{OH - C - C - H}}\] bond. More substituted alcohol is the major product. It is an electrophilic addition type of reaction.
Complete solution:
As we know that Oxymercuration-demercuration reaction is a hydration reaction so the product of the reaction will be alcohol.Hence, Option (A) and (D) are the incorrect answers.
Now we will see the detail mechanism of the Oxymercuration-demercuration reaction.
Step1: Formation of cyclic mercurinium ion: Nucleophilic attack of \[\pi \] electrons of \[{\text{C = C}}\]on electrophilic \[{\text{Hg}}\] and loss of an acetate ion.
Step2: Opening of mercurinium ion by nucleophilic attack of water. Attack of water takes place according to Markovnikov’s rule, that is it attacks on the more substituted carbon atom.
Step3: Deprotonation of oxonium ion by base acetate ion.
Step4: Breaking of \[{\text{C - Hg}}\] bond and formation of \[{\text{C - H}}\] by reduction with\[{\text{NaB}}{{\text{H}}_{\text{4}}}\].
Thus, option (D) is incorrect as the product is not diol.
Thus, the correct options are (B).
Note:Oxymercuration-demercuration reaction involves the transformation of \[{\text{C = C}}\] to \[{\text{OH - C - C - H}}\] bond. More substituted alcohol is the major product. It is an electrophilic addition type of reaction.
Recently Updated Pages
Can anyone list 10 advantages and disadvantages of friction
What are the Components of Financial System?
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
What is the specific heat capacity of ice water and class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE