Answer
Verified
399.3k+ views
Hint: When a pair of electrons are shared by two atoms, a covalent bond is formed. So to determine the pair of electrons shared by the two oxygen atoms, we need to find the bonding in the oxygen molecule.
Complete answer:
To determine the bonding in an oxygen molecule, we first need to know its molecular formula. The molecular formula of oxygen molecules is ${{O}_{2}}$.
Now, the chemical bonding in a molecule can be depicted using the Lewis dot structures.
To draw the Lewis dot structure of oxygen molecule,
- We first need to know the electronic configuration of oxygen atoms.
\[^{8}O=1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}\]
- Determine the number of valence electrons.
Oxygen atom has 6 electrons in its outermost (n = 2) shell and hence it has 6 valence electrons.
The valence electrons are the ones that participate in molecule or chemical bond formation.
- Arrange the valence electrons around the oxygen atoms.
- Since the oxygen atom has 6 valence electrons, it needs 2 electrons to completely fill its outermost shell and satisfy the octet rule.
The two electrons required by the oxygen atom can be obtained by the other oxygen molecule by sharing.
Each oxygen atom will share two electrons with the other oxygen atom and form two covalent bonds or a double bond.
So we can see that the two oxygen atoms in an oxygen molecule share 2 pairs of electrons with each other
Note:
When there exists a charge atom, electrons equal to the magnitude of the charge are added (in case of a negatively charged anion) or subtracted (in case of a positive charged cation) from the Lewis dot diagram.
Complete answer:
To determine the bonding in an oxygen molecule, we first need to know its molecular formula. The molecular formula of oxygen molecules is ${{O}_{2}}$.
Now, the chemical bonding in a molecule can be depicted using the Lewis dot structures.
To draw the Lewis dot structure of oxygen molecule,
- We first need to know the electronic configuration of oxygen atoms.
\[^{8}O=1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}\]
- Determine the number of valence electrons.
Oxygen atom has 6 electrons in its outermost (n = 2) shell and hence it has 6 valence electrons.
The valence electrons are the ones that participate in molecule or chemical bond formation.
- Arrange the valence electrons around the oxygen atoms.
- Since the oxygen atom has 6 valence electrons, it needs 2 electrons to completely fill its outermost shell and satisfy the octet rule.
The two electrons required by the oxygen atom can be obtained by the other oxygen molecule by sharing.
Each oxygen atom will share two electrons with the other oxygen atom and form two covalent bonds or a double bond.
So we can see that the two oxygen atoms in an oxygen molecule share 2 pairs of electrons with each other
Note:
When there exists a charge atom, electrons equal to the magnitude of the charge are added (in case of a negatively charged anion) or subtracted (in case of a positive charged cation) from the Lewis dot diagram.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE