Question

Particle A makes a perfectly elastic collision with another particle B at rest. They fly apart in opposite directions with equal speeds. If their masses are $m_A$ and $m_B$ respectively. Then:
A.2$m_A=m_B$
B.$3m_A=m_B$
C.4$m_A=m_B$
D.$\sqrt{3}{m}_A=m_B$

Answer 1

Hint: Apply law of conservation of linear momentum and find the ratio of initial velocity and final velocity. Then, applying the law of conservation, find the ratio of initial and final velocities. Equate both the ratios and find the mass of both the particles.

Complete answer:

Given: Initial velocity of particle B=0
Final velocity of both the particles is the same.
Let initial velocity of particle A be u .
Final velocity of both the particles i.e. A and B be v
According to the law of conservation of momentum,
$m_{A}u+m_B\times 0=m_{A}v+m_B(-v)$
$\Rightarrow m_{A}u=m_{A}v+m_B(-v)$
$\Rightarrow m_{A}u=v(m_A-m_B)$
$\Rightarrow {\displaystyle \frac{u}{v}}={\displaystyle \frac{(m_A-m_B)}{m_A}}$...(1)
Now, applying law of conservation of energy we get,
${\displaystyle \frac{1}{2}}{m}_A{u}^2+12m_B{0}^2=12m_A{v}^2+12m_B{v}^2$
$\Rightarrow {\displaystyle \frac{1}{2}}{m}_A{u}^2=12m_A{v}^2+12m_B{v}^2$
$\Rightarrow {\displaystyle \frac{1}{2}}{m}_A{u}^2={\displaystyle \frac{1}{2}}{v}^2(m_A+m_B)$
$\Rightarrow {\displaystyle \frac{u^2}{v^2}}={\displaystyle \frac{m_A+m_B}{m_A}}$
$\Rightarrow {\displaystyle \frac{u}{v}}=\sqrt{{\displaystyle \frac{m_A+m_B}{m_A}}}$ ...(2)
Equating equation. (1) and equation. (2) we get,
${\displaystyle \frac{(m_A-m_B)}{m_A}}=\sqrt{{\displaystyle \frac{m_A+m_B}{m_A}}}$
Squaring above equation we get,
${\displaystyle \frac{m_A^2-2m_A{m}_B+m_B^2}{m_A^2}}={\displaystyle \frac{m_A+m_B}{m_A}}$
$\Rightarrow {\displaystyle \frac{m_A^2-2m_A{m}_B+m_B^2}{m_B^2}}=m_A^2+m_A+m_B$
$\Rightarrow m_B^2=m_A+m_B$
$\Rightarrow m_B=3m_A$

So, the correct answer is option B i.e. $3m_A=m_B$.

Note:
To solve these types of questions, students must have knowledge about the conservation laws and the collisions. When two particles come together, collision takes place. There are two types of collisions namely: 1) Elastic Collision 2) Inelastic Collision. So, to check whether a collision is elastic or inelastic, you can equate kinetic energy of the particles. After a collision, if the kinetic energy remains the same as before, then it is called an elastic collision. After a collision, if the kinetic energy does not remain the same as before, then it is called an elastic collision.