
Potassium has a bcc structure with nearest neighbour distance $ 4.52{{\text{A}}^{\text{o}}} $ , its atomic weight is 39. Its density (in kg $ {{\text{m}}^{ - 1}} $ ) will be:
(A) 454
(B) 804
(C) 852
(D) 908
Answer
549.6k+ views
Hint: Density is equal to mass per volume. Density is also known as volumetric mass density or specific mass. Density of any material varies with temperature and pressure. To solve this question, we will use the concept of solid state and density. We shall calculate the edge length and use it in the formula given.
Formula used: Density = $ \dfrac{{M \times Z}}{{{N_A} \times {a^3}}} $
Distance between two atoms = $ \dfrac{{a\sqrt 3 }}{2} $
Here M is the molecular mass of potassium in kg, Z is number of atoms per unit cell, $ {N_A} $ is Avogadro’s number that is $ 6.022 \times {10^{23}} $ and ‘a’ is the length of edge of unit cell.
Complete step by step solution:
Unit cell is the smallest repeating unit of crystal lattice. Unit cell is the building block of a crystal.
A Body-centred cubic (bcc) unit cell has atoms at each corner of the cube and an atom at the centre of the structure.
In bcc the distance between two nearest atoms is given by $ \dfrac{{a\sqrt 3 }}{2} $ .
$ \dfrac{{a\sqrt 3 }}{2} $ = $ 4.52{A^ \circ } $
Therefore, a = $ \dfrac{{4.52 \times 2}}{{\sqrt 3 }} $
Density = $ \dfrac{{39 \times 2 \times {{10}^{ - 3}}}}{{6.022 \times {{10}^{23}} \times {{(\dfrac{{2 \times 4.52 \times {{10}^{ - 10}}}}{{\sqrt 3 }})}^3}}} $
Here we have substituted Z as 2 as the number of atoms in bcc are two.
Here, the molecular weight of potassium is given as 39 grams so to convert it into kilogram that is the S.I unit we divide it by 1000 that is multiplied by $ {10^{ - 3}} $ .
Density = 908 $ {\text{kg}}{{\text{m}}^{ - 3}} $
So, the correct answer is option D.
Note:
In body centred cubic the atoms are present at:
In Body–centred cubic unit cell every corner has an atom.
There is one atom present at the centre of the cube.
According to this body- centred cubic, the atom at the body centres completely belongs to the unit cell in which it is present.
Formula used: Density = $ \dfrac{{M \times Z}}{{{N_A} \times {a^3}}} $
Distance between two atoms = $ \dfrac{{a\sqrt 3 }}{2} $
Here M is the molecular mass of potassium in kg, Z is number of atoms per unit cell, $ {N_A} $ is Avogadro’s number that is $ 6.022 \times {10^{23}} $ and ‘a’ is the length of edge of unit cell.
Complete step by step solution:
Unit cell is the smallest repeating unit of crystal lattice. Unit cell is the building block of a crystal.
A Body-centred cubic (bcc) unit cell has atoms at each corner of the cube and an atom at the centre of the structure.
In bcc the distance between two nearest atoms is given by $ \dfrac{{a\sqrt 3 }}{2} $ .
$ \dfrac{{a\sqrt 3 }}{2} $ = $ 4.52{A^ \circ } $
Therefore, a = $ \dfrac{{4.52 \times 2}}{{\sqrt 3 }} $
Density = $ \dfrac{{39 \times 2 \times {{10}^{ - 3}}}}{{6.022 \times {{10}^{23}} \times {{(\dfrac{{2 \times 4.52 \times {{10}^{ - 10}}}}{{\sqrt 3 }})}^3}}} $
Here we have substituted Z as 2 as the number of atoms in bcc are two.
Here, the molecular weight of potassium is given as 39 grams so to convert it into kilogram that is the S.I unit we divide it by 1000 that is multiplied by $ {10^{ - 3}} $ .
Density = 908 $ {\text{kg}}{{\text{m}}^{ - 3}} $
So, the correct answer is option D.
Note:
In body centred cubic the atoms are present at:
In Body–centred cubic unit cell every corner has an atom.
There is one atom present at the centre of the cube.
According to this body- centred cubic, the atom at the body centres completely belongs to the unit cell in which it is present.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

