Question

Prove impulse- momentum theorem.

Answer 1

Hint:Impulse momentum theorem equals the impulse and the change in the momentum of the body. From the formula of the force, apply integrals in it with the limits of time and the momentum and apply the impulse formula to derive the impulse momentum theorem of the body.

Useful formula:
(1) The formula of force is given by
$\overrightarrow{F}={\displaystyle \frac{d\overrightarrow{p}}{d\overrightarrow{t}}}$
Where $F$ is the force acting on the body, ${\displaystyle \frac{d\overrightarrow{p}}{d\overrightarrow{t}}}$ is the rate of change of momentum with respect to that of time.
(2) The formula of the impulse is given by
$J=\overrightarrow{F}t$
Where $J$ is the impulse and $t$ is the time taken.

Complete step by step solution:
The impulse- momentum theorem states that the impulse is equal to the change in the momentum.
In order to prove the above theorem, the formula of the force is taken,
$\overrightarrow{F}={\displaystyle \frac{d\overrightarrow{p}}{d\overrightarrow{t}}}$
$\overrightarrow{F}d\overrightarrow{t}=d\overrightarrow{p}$
By integrating the above equation, we get
$\int \overrightarrow{F}d\overrightarrow{t}=\int d\overrightarrow{p}$
Let us assume that the force is the constant and the $p_1$ and $p_2$ are the momentum of the body at the time $t=0$ and $t=t$ respectively. Substituting these parameters in the above equation, we get
$\underset{0}{\overset{t}{\int }}\overrightarrow{F}d\overrightarrow{t}=\underset{p_1}{\overset{p_2}{\int }}d\overrightarrow{p}$
$\overrightarrow{F}\underset{0}{\overset{t}{\int }}d\overrightarrow{t}=\underset{p_1}{\overset{p_2}{\int }}d\overrightarrow{p}$
By substituting the limit in the integral, we get
$\overrightarrow{F}\left(t-0\right)={\left[p\right]}_{{\overrightarrow{p}}_1}^{{\overrightarrow{p}}_2}$
By simplifying the above equation, we get
$$\overrightarrow{F}t=\left[{\overrightarrow{p}}_1-{\overrightarrow{p}}_2\right]$$
From the formula of the impulse, it is clear that the
$J=\left[{\overrightarrow{p}}_1-{\overrightarrow{p}}_2\right]$
Hence the impulse of the body is equal to the change in the momentum of it.

Hence proved.

Note:Remember that while integrating the parameters, the constant integral is constant. So it is taken outside the integral. While applying the limits, the upper limit is applied first and then from it the lower limit is subtracted. In collision of the bodies, the body experiences the impulse that is due to change in momentum of it.