
Prove that is an irrational number?
Answer
490.2k+ views
Hint: In this question, we will use the contradiction method of solving the question. First assume that the given number is a rational number of the where a and b have no common factor other than 1 and b 0. After this we follow a procedure to contradict our assumption.
Complete step-by-step answer:
The given number is .
Now suppose that the given number is a rational number of the form , where a and b have no common factor other than 1 and b 0.
. =
On squaring both sides, we get:
On further solving, we have:
2 divides .
It will also divide and hence it will divide ‘a’.
Now, let a =2k
Putting the value of ‘a’ in above equation, we get:
On further solving, we get:
2 divides .
It will also divide and hence it will divide ‘b’.
Therefore, we can say that 2 is the common factor of both ‘a’ and ‘b’.
This contradicts our assumption that ‘a’ and ‘b’ have no common factor other than 1
Hence, the number is an irrational number.
Note: Solving such forms of problems requires a determined approach of making an assumption which is the exact opposite of what is being asked and then contradicting that assumption therefore reaching to the proof. You should know that the product of a rational and an irrational number is always irrational. For example- is an irrational number.
Complete step-by-step answer:
The given number is
Now suppose that the given number is a rational number of the form
On squaring both sides, we get:
On further solving, we have:
Now, let a =2k
Putting the value of ‘a’ in above equation, we get:
On further solving, we get:
Therefore, we can say that 2 is the common factor of both ‘a’ and ‘b’.
This contradicts our assumption that ‘a’ and ‘b’ have no common factor other than 1
Hence, the number
Note: Solving such forms of problems requires a determined approach of making an assumption which is the exact opposite of what is being asked and then contradicting that assumption therefore reaching to the proof. You should know that the product of a rational and an irrational number is always irrational. For example-
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