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Prove that 2 is an irrational number?

Answer
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Hint: In this question, we will use the contradiction method of solving the question. First assume that the given number is a rational number of the ab where a and b have no common factor other than 1 and b 0. After this we follow a procedure to contradict our assumption.

Complete step-by-step answer:
The given number is2.
Now suppose that the given number is a rational number of the form ab, where a and b have no common factor other than 1 and b 0.
.2 =ab
On squaring both sides, we get:
(2)2=a2b2
On further solving, we have:
2=a2b2
2b2=a2
2 divides b2.
It will also divide a2and hence it will divide ‘a’.
Now, let a =2k
Putting the value of ‘a’ in above equation, we get:
2b2=(2k)2
On further solving, we get:
2b2=4k2
b2=2k2
2 divides k2.
It will also divide b2and hence it will divide ‘b’.
Therefore, we can say that 2 is the common factor of both ‘a’ and ‘b’.
This contradicts our assumption that ‘a’ and ‘b’ have no common factor other than 1
Hence, the number 2 is an irrational number.

Note: Solving such forms of problems requires a determined approach of making an assumption which is the exact opposite of what is being asked and then contradicting that assumption therefore reaching to the proof. You should know that the product of a rational and an irrational number is always irrational. For example- 22 is an irrational number.
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