
Prove that two triangles having the same base (or equal bases) have equal areas between the same parallels.
Answer
511.5k+ views
Hint: Assume two triangles between two parallel lines having the same base. We know the formula of the area of the triangle, . We also know the property that the distance between parallel lines is always constant. So, each perpendicular distance between the parallel lines is always equal to each other. Now, solve it further.
Complete step-by-step answer:
Assume two line segments AB and CD parallel to each other and two triangles which are and having the same base EG.
Let the distance between the parallel lines AB and CD be x.
In , we have,
EG as the base of the ,
FI is the height which is also perpendicular to the base EG.
We know the formula of the area of the triangle,
Now, using this formula to get the area of the .
Area of = ………………………..(1)
In , we have,
EG as the base of the ,
HJ is the height which is also perpendicular to the base EG.
We know the formula of the area of the triangle,
Now, using this formula to get the area of the .
Area of = ………………..(2)
We know the property that the distance between parallel lines is always constant. So, each perpendicular distance between the parallel lines is always equal to each other.
Using this property, we can say that,
FI=HJ ………..(3)
From equation (2), and equation (3), we get
Area of = ………………..(4)
From equation (1), we have
Area of = .
Now, we can say that equation (1) and equation (4) are equal to each other.
So, Area of = Area of .
Therefore, two triangles having the same base (or equal bases) have equal areas between the same parallels.
Hence, proved.
Note: In this question, one may think to use heron’s formula for the area of the triangle. That is, . But if we use this formula, then we will not be able to use the property of parallel lines, and also this formula will make our solution complex to solve. Therefore, don’t think to use heron’s formula here.
Complete step-by-step answer:

Assume two line segments AB and CD parallel to each other and two triangles which are
Let the distance between the parallel lines AB and CD be x.
In
EG as the base of the
FI is the height which is also perpendicular to the base EG.
We know the formula of the area of the triangle,
Now, using this formula to get the area of the
Area of
In
EG as the base of the
HJ is the height which is also perpendicular to the base EG.
We know the formula of the area of the triangle,
Now, using this formula to get the area of the
Area of
We know the property that the distance between parallel lines is always constant. So, each perpendicular distance between the parallel lines is always equal to each other.
Using this property, we can say that,
FI=HJ ………..(3)
From equation (2), and equation (3), we get
Area of
From equation (1), we have
Area of
Now, we can say that equation (1) and equation (4) are equal to each other.
So, Area of
Therefore, two triangles having the same base (or equal bases) have equal areas between the same parallels.
Hence, proved.
Note: In this question, one may think to use heron’s formula for the area of the triangle. That is,
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