Question

What is the ratio by the mass of combining elements in glucose $\left( {{C_6}{H_{12}}{O_6}} \right)$ ?

Answer 1

Hint: We have to know that, in science, mass proportion, frequently called "percent creation by mass," is the extent of a specific particle that comprises every atom's constituent components.

Complete answer:
In the given compound is glucose. The chemical formula of the glucose is $\left( {{C_6}{H_{12}}{O_6}} \right)$ .
We can discover the proportion of the mass of the atom by following the given substance:
Recognize the recipe of the compound or particle. Utilizing the equation to decide the quantity of particles present in every component of the compound or atom. Increase the nuclear load of every component with the quantity of molecules of that specific component. Likewise, do it for every one of the components in the particle or compound.
Allow us to search for the nuclear masses of carbon, hydrogen, and oxygen.
For,
The atomic number of carbon = $12$
The atomic number of hydrogen = $1$
The atomic number of oxygen = $16$
Then, the mass of combining elements in glucose,
For carbon,
$12 \times 6 = 72$
For hydrogen,
$12 \times 1 = 12$
For oxygen,
$16 \times 6 = 96$
Where,
All the above values are divided by the small value of them.
Therefore,
For carbon atom,
$\dfrac{{72}}{{12}} = 6$
For hydrogen atom,
$\dfrac{{12}}{{12}} = 1$
For oxygen atom,
$\dfrac{{96}}{{12}} = 8$
The ratio of the mass of combining elements in glucose is given,
$C:H:O = 6:1:8$

Note:
In the molar proportion strategy, a property of an answer is plotted against the molar proportion of the two reactants, the grouping of one being kept steady. The stoichiometry of the complex or edifices shaped is reasoned from the situation of breaks in the bend. For this reason the molar-proportion strategy is frequently utilized.