Question

What is the ratio of the highest marks to the lowest marks obtained by the student?

A. 2:11
B. 9:2
C. 2:9
D. 11:2

Answer 1

Hint: First write the lowest and highest marks obtained by the student. Then, write the numbers in the fraction such that highest marks is in numerator and lowest marks is in denominator. Reduce to lowest term and get the required ratio.

Complete step-by-step answer:
We have to find the ratio of the highest marks to the lowest marks obtained by the student.
From the graph, we can see that the highest marks obtained by the student is in mathematics , which is 90.
Similarly, we can see that the lowest marks obtained by the student is in History which is equal to 20 marks.
For finding the ratio, we will write the lowest marks and highest marks in fractional form such that highest marks is in numerator and lowest marks is in denominator.
That is,
${\displaystyle \frac{90}{20}}$
But, the ratio is always written in lowest form.
Hence, the ratio is ${\displaystyle \frac{9}{2}}$
If a ratio is written in the form ${\displaystyle \frac{a}{b}}$ , it is also equivalent to $a:b$
Then, the ratio of the highest marks to the lowest marks obtained by the student is 9:2.
Hence, option B is correct.

Note: While writing the ratio, one has to take care of the order of the numbers written. If we want the ratio of the highest marks to the lowest marks obtained by the student, then the highest number should come in numerator and lowest marks should be written in denominator.