Answer
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Hint: We first try to find the condition for numbers to be hundredth valued where the numbers are multiple of 100. Then based on the first two digits of number 9116, we find the interval. Then we zero it down to the nearest one based on the difference.
Complete step-by-step answer:
The process of finding the nearest hundred is dependent on finding the nearest number being a multiple of 100.
The number is 9116. If we find the nearest hundred to 9116 the last two digits of the number will be 0.
The numbers we are going to choose have to consist of the two zeroes at the end.
The range we are going to choose is from 9000 to 9200.
We know that $9000<9116$ and $9116<9200$.
Both 9000 and 9200 are multiples of 100 as they have two zeroes at the end.
We chose these two depending on the first two digits where $90<91$ and $91<92$.
Also, we need to remember that there is one more number of hundred in between 9000 to 9200 and that is 9100.
We can zero it down to 9100 to 9200.
Now we need to find which one is closer to 9116.
We find the differences.
The difference of 9116 from 9100 is $9116-9100=16$ and the difference of 9116 from 9200 is $9200-9116=84$.
We can see 9116 is closer to 9100 than 9200.
Therefore, rounding off 9116 to the nearest hundred we get 9100.
Note: The process of rounding off decimal and integer numbers is different. For integer values we need to always do the trial and error method. But in case of decimals, we follow for numbers less or greater than value of 5.
Complete step-by-step answer:
The process of finding the nearest hundred is dependent on finding the nearest number being a multiple of 100.
The number is 9116. If we find the nearest hundred to 9116 the last two digits of the number will be 0.
The numbers we are going to choose have to consist of the two zeroes at the end.
The range we are going to choose is from 9000 to 9200.
We know that $9000<9116$ and $9116<9200$.
Both 9000 and 9200 are multiples of 100 as they have two zeroes at the end.
We chose these two depending on the first two digits where $90<91$ and $91<92$.
Also, we need to remember that there is one more number of hundred in between 9000 to 9200 and that is 9100.
We can zero it down to 9100 to 9200.
Now we need to find which one is closer to 9116.
We find the differences.
The difference of 9116 from 9100 is $9116-9100=16$ and the difference of 9116 from 9200 is $9200-9116=84$.
We can see 9116 is closer to 9100 than 9200.
Therefore, rounding off 9116 to the nearest hundred we get 9100.
Note: The process of rounding off decimal and integer numbers is different. For integer values we need to always do the trial and error method. But in case of decimals, we follow for numbers less or greater than value of 5.
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