
Solve the following simultaneous equation:
$
x + y = 8 \\
3x + 4y = 25 \\
$
Answer
521.1k+ views
Hint: Find the value of one variable in the form of the other variable from the first equation. Then put it in the second equation.
Complete step-by-step answer:
The given simultaneous equation is:
$
x + y = 8 .....(i) \\
3x + 4y = 25 .....(ii) \\
$
From equation $(i)$, we have:
$
\Rightarrow x + y = 8, \\
\Rightarrow x = 8 - y \\
$
Putting this value in equation $(ii)$, we’ll get:
$
\Rightarrow 3\left( {8 - y} \right) + 4y = 25, \\
\Rightarrow 24 - 3y + 4y = 25, \\
\Rightarrow y = 1 \\
$
Putting $y = 1$ in equation $(i)$, we’ll get:
$
\Rightarrow x + 1 = 8, \\
\Rightarrow x = 7 \\
$
Thus, the solution of the simultaneous equation is $x = 7$ and $y = 1$.
Note: The method used above is called substitution method. We can use another method called addition method. In this method we make the coefficients of any one variable negative of each other in both the equations by multiplying equations with suitable constants. And then add both the equations to get one variable eliminated.
Complete step-by-step answer:
The given simultaneous equation is:
$
x + y = 8 .....(i) \\
3x + 4y = 25 .....(ii) \\
$
From equation $(i)$, we have:
$
\Rightarrow x + y = 8, \\
\Rightarrow x = 8 - y \\
$
Putting this value in equation $(ii)$, we’ll get:
$
\Rightarrow 3\left( {8 - y} \right) + 4y = 25, \\
\Rightarrow 24 - 3y + 4y = 25, \\
\Rightarrow y = 1 \\
$
Putting $y = 1$ in equation $(i)$, we’ll get:
$
\Rightarrow x + 1 = 8, \\
\Rightarrow x = 7 \\
$
Thus, the solution of the simultaneous equation is $x = 7$ and $y = 1$.
Note: The method used above is called substitution method. We can use another method called addition method. In this method we make the coefficients of any one variable negative of each other in both the equations by multiplying equations with suitable constants. And then add both the equations to get one variable eliminated.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
A number is chosen from 1 to 20 Find the probabili-class-10-maths-CBSE

Find the area of the minor segment of a circle of radius class 10 maths CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

A gulab jamun contains sugar syrup up to about 30 of class 10 maths CBSE

Leap year has days A 365 B 366 C 367 D 368 class 10 maths CBSE
