State Newton's second law of motion, in terms of momentum.
Answer
Verified
474.9k+ views
HINT-The second law states that the rate of change of momentum of a body is directly proportional to
the force applied OR Force equals mass times acceleration.
COMPLETE STEP BY STEP SOLUTION
According to the second law of motion the force applied on a body is proportional to the rate of change of momentum of the body.
ie; force \[ \propto \] change in momentum with respect to time
Or \[F \propto \dfrac{{dp}}{{dt}}\] ……………………...(1)
Where p= momentum and we know that momentum is equal to the product of mass and velocity ie,P=mv
Putting the value of momentum in equation (1)
\[F \propto \dfrac{{d(mv)}}{{dt}}\]
Or \[F = \kappa \dfrac{{d(mv)}}{{dt}}\] ………………….(2)
Where k is constant of proportionality
Since k=1 and mass is considered to be constant here so then in equation (2)
\[\
F = 1m \dfrac{{dv}}{{dt}} \\
\Rightarrow F = m \dfrac{{dv}}{{dt}} \\
\ \]
Since acceleration a measurement of how quickly an object is changing speed or change in velocity with respect to time ie; \[a = \dfrac{{dv}}{{dt}}\]
Therefore F=ma and Here,
Force is directly proportional to mass and acceleration. Imagine a ball of a certain mass moving at a certain acceleration. This ball has a certain force
If you double the mass, you double the force. If you double the acceleration, you double the force.
And if you double the mass and the acceleration then,
(2m)(2a) = 4F Doubling the mass and the acceleration quadruples the force.
Note :- F = ma basically means that the force of an object comes from its mass and its acceleration
Something very massive (high mass) that’s changing speed very slowly (low acceleration), like a glacier, can still have great force
Something very small (low mass) that’s changing speed very quickly (high acceleration), like a bullet, can still have a great force. Something very small changing speed very slowly will have a very weak force
the force applied OR Force equals mass times acceleration.
COMPLETE STEP BY STEP SOLUTION
According to the second law of motion the force applied on a body is proportional to the rate of change of momentum of the body.
ie; force \[ \propto \] change in momentum with respect to time
Or \[F \propto \dfrac{{dp}}{{dt}}\] ……………………...(1)
Where p= momentum and we know that momentum is equal to the product of mass and velocity ie,P=mv
Putting the value of momentum in equation (1)
\[F \propto \dfrac{{d(mv)}}{{dt}}\]
Or \[F = \kappa \dfrac{{d(mv)}}{{dt}}\] ………………….(2)
Where k is constant of proportionality
Since k=1 and mass is considered to be constant here so then in equation (2)
\[\
F = 1m \dfrac{{dv}}{{dt}} \\
\Rightarrow F = m \dfrac{{dv}}{{dt}} \\
\ \]
Since acceleration a measurement of how quickly an object is changing speed or change in velocity with respect to time ie; \[a = \dfrac{{dv}}{{dt}}\]
Therefore F=ma and Here,
Force is directly proportional to mass and acceleration. Imagine a ball of a certain mass moving at a certain acceleration. This ball has a certain force
If you double the mass, you double the force. If you double the acceleration, you double the force.
And if you double the mass and the acceleration then,
(2m)(2a) = 4F Doubling the mass and the acceleration quadruples the force.
Note :- F = ma basically means that the force of an object comes from its mass and its acceleration
Something very massive (high mass) that’s changing speed very slowly (low acceleration), like a glacier, can still have great force
Something very small (low mass) that’s changing speed very quickly (high acceleration), like a bullet, can still have a great force. Something very small changing speed very slowly will have a very weak force
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE
What organs are located on the left side of your body class 11 biology CBSE
Define least count of vernier callipers How do you class 11 physics CBSE