Answer
Verified
447k+ views
Hint:-Here we will use light year and one day in terms of m and second respectively then substitute them in the value of speed of light so that we can get the speed of light in light year per day
Complete step by step solution
The light-year is a unit of distance and is used to measure astronomical distances and is equivalent to about 9.46 trillion kilometres (9.46 x 1012 km) or 5.88 trillion miles (5.88 x 1012 mi).
Since speed of light is $ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$ $3 \times {10^8}\dfrac{m}{s}$.............(1)
So here in the place of m we can substitute the value of the light year as 1m and in second we can substitute days as 1 second.
$\because 1ly = 9.46 \times {10^{15}}m$
So I m will be equal to $\dfrac{{1ly}}{{9.46 \times {{10}^{15}}}} = 1m$
And we have one day is equal to \[86400s\]
So, $\dfrac{{1day}}{{86400}} = s$
Then from equation (1)
speed of light in light year per day is
$ \Rightarrow 3 \times {10^8}\dfrac{{\dfrac{1}{{9.46 \times {{10}^{15}}m}}}}{{\dfrac{{1day}}{{86400}}}}$
$ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$
Note:-The speed of light in vacuum air or in space is a universal physical constant used in many areas of physics. Its exact value is around 299792458 metres per second which is approximately 300000 km/s, or 186000 miles/s. it is generally denoted by c. Speed of light in other medium like glass, water is less than
It was first demonstrated by Ole Christensen Rømer in 1676 that light travels at a finite speed (non-instantaneously) by studying the apparent motion of Jupiter's moon Io.
Complete step by step solution
The light-year is a unit of distance and is used to measure astronomical distances and is equivalent to about 9.46 trillion kilometres (9.46 x 1012 km) or 5.88 trillion miles (5.88 x 1012 mi).
Since speed of light is $ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$ $3 \times {10^8}\dfrac{m}{s}$.............(1)
So here in the place of m we can substitute the value of the light year as 1m and in second we can substitute days as 1 second.
$\because 1ly = 9.46 \times {10^{15}}m$
So I m will be equal to $\dfrac{{1ly}}{{9.46 \times {{10}^{15}}}} = 1m$
And we have one day is equal to \[86400s\]
So, $\dfrac{{1day}}{{86400}} = s$
Then from equation (1)
speed of light in light year per day is
$ \Rightarrow 3 \times {10^8}\dfrac{{\dfrac{1}{{9.46 \times {{10}^{15}}m}}}}{{\dfrac{{1day}}{{86400}}}}$
$ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$
Note:-The speed of light in vacuum air or in space is a universal physical constant used in many areas of physics. Its exact value is around 299792458 metres per second which is approximately 300000 km/s, or 186000 miles/s. it is generally denoted by c. Speed of light in other medium like glass, water is less than
It was first demonstrated by Ole Christensen Rømer in 1676 that light travels at a finite speed (non-instantaneously) by studying the apparent motion of Jupiter's moon Io.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE