
Test whether the following relation is (1) reflexive (2) symmetric and (3) transitive R on Z defined by (a,b) \[\in R\Leftrightarrow \left| a-b \right|\le 5.\]
Answer
619.2k+ views
Hint: we will have to know about the term reflexive, symmetric and transitive so that we can understand the question. For a relation R in set A. The relation said to be reflexive if (a,a) \[\in \]R for every a \[\in \]A, for symmetric relation if (a,b) \[\in \]R then (b,a) \[\in \]R and for transitive relation if (a,b) \[\in \]R, (b,c) \[\in \]R then (a,c) \[\in \]R.
Complete step-by-step answer:
Given the relation is R on Z defined by (a,b) \[\in R\Leftrightarrow \left| a-b \right|\le 5.\]
Now, we will check the condition of reflexive, symmetric and transitive for the above relation.
Clearly, we can say that the above relation is reflexive as \[\forall a\in Z,(a,a)\in R\text{ since }\left| a-a \right|=0\le 5.\]
\[\begin{align}
& \text{Also the relation is symmetric as }\left| b-a \right|=\left| a-b \right|\le 5\text{ so (a,b)}\in R,\forall a,b\in Z. \\
& \text{But the relation is not transitive as (1,2) }\in \text{R,(2,7)}\in \text{R but (1,7)}\notin \text{R}\text{.} \\
\end{align}\]
Therefore, the above given relation is reflexive, symmetric but not transitive.
NOTE: Just remember the term reflexive, symmetric and transitive so you can easily understand the given question and solve it easily. The condition for the relation to be reflexive, symmetric and transitive are mentioned in the hint.
Also, remember the point that if any relation is symmetric,reflexive as well as transitive then the relation is known as equivalence relation.In many questions we have to find the equivalence relation also so it is very important to remember this point.
Complete step-by-step answer:
Given the relation is R on Z defined by (a,b) \[\in R\Leftrightarrow \left| a-b \right|\le 5.\]
Now, we will check the condition of reflexive, symmetric and transitive for the above relation.
Clearly, we can say that the above relation is reflexive as \[\forall a\in Z,(a,a)\in R\text{ since }\left| a-a \right|=0\le 5.\]
\[\begin{align}
& \text{Also the relation is symmetric as }\left| b-a \right|=\left| a-b \right|\le 5\text{ so (a,b)}\in R,\forall a,b\in Z. \\
& \text{But the relation is not transitive as (1,2) }\in \text{R,(2,7)}\in \text{R but (1,7)}\notin \text{R}\text{.} \\
\end{align}\]
Therefore, the above given relation is reflexive, symmetric but not transitive.
NOTE: Just remember the term reflexive, symmetric and transitive so you can easily understand the given question and solve it easily. The condition for the relation to be reflexive, symmetric and transitive are mentioned in the hint.
Also, remember the point that if any relation is symmetric,reflexive as well as transitive then the relation is known as equivalence relation.In many questions we have to find the equivalence relation also so it is very important to remember this point.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

