![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
The angles of a quadrilateral are in the ratio 2 : 3 : 4 : 6. Find the measure of each of the angles.
Answer
482.4k+ views
Hint: We will first discuss the fact that sum of angles of quadrilateral is ${360^ \circ }$. Then, we will just assume the angle and find all other angles using the ratio and sum them all up and equate to ${360^ \circ }$, we will have with us, the measures of all the angles.
Complete step-by-step answer: We will use the fact that the sum of angles of a quadrilateral is ${360^ \circ }$.
Sum of angles of quadrilateral is ${360^ \circ }$ ………(1)
Now, we have the ratio of angles as 2 : 3 : 4 : 6.
Let the first angle be $2x$, so then according to the ratio, the angles will be $2x, 3x, 4x, 6x$.
Now using (1), we will have:-
$2x + 3x + 4x + 6x = {360^ \circ }$
Simplifying the LHS, we will have:-
$15x = {360^ \circ }$
Taking the 15 from multiplication in LHS to division in RHS, we will have:-
\[x = \dfrac{{{{360}^ \circ }}}{{15}} = \dfrac{{{{72}^ \circ }}}{3} = {24^ \circ }\].
Hence, $x = {24^ \circ }$.
So, the angles will be ${48^ \circ },{72^ \circ },{96^ \circ },{144^ \circ }$.
Hence, the answer is ${48^ \circ },{72^ \circ },{96^ \circ },{144^ \circ }$.
Note: The students might leave the answer part after finding the value of x, but they must remember that they are asked about the measure of angles, not the value to solve them. So, we must complete our answer by substituting the value of x.
Complete step-by-step answer: We will use the fact that the sum of angles of a quadrilateral is ${360^ \circ }$.
Sum of angles of quadrilateral is ${360^ \circ }$ ………(1)
Now, we have the ratio of angles as 2 : 3 : 4 : 6.
Let the first angle be $2x$, so then according to the ratio, the angles will be $2x, 3x, 4x, 6x$.
Now using (1), we will have:-
$2x + 3x + 4x + 6x = {360^ \circ }$
Simplifying the LHS, we will have:-
$15x = {360^ \circ }$
Taking the 15 from multiplication in LHS to division in RHS, we will have:-
\[x = \dfrac{{{{360}^ \circ }}}{{15}} = \dfrac{{{{72}^ \circ }}}{3} = {24^ \circ }\].
Hence, $x = {24^ \circ }$.
So, the angles will be ${48^ \circ },{72^ \circ },{96^ \circ },{144^ \circ }$.
Hence, the answer is ${48^ \circ },{72^ \circ },{96^ \circ },{144^ \circ }$.
Note: The students might leave the answer part after finding the value of x, but they must remember that they are asked about the measure of angles, not the value to solve them. So, we must complete our answer by substituting the value of x.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
When people say No pun intended what does that mea class 8 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How many ounces are in 500 mL class 8 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which king started the organization of the Kumbh fair class 8 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is BLO What is the full form of BLO class 8 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Advantages and disadvantages of science
![arrow-right](/cdn/images/seo-templates/arrow-right.png)