Question

The compound $buta-1,2-dien$ consists of:
A.only $sp-$ hybridized carbon atom
B.only $s{p}^2$ hybridized carbon atom
C.both $sp$ and $s{p}^2$ hybridized carbon atom
D.$sp$ , $s{p}^2$ and $s{p}^3$ hybridized carbon atom

Answer 1

Hint:Hybridization can be defined as the mixing of two atomic orbitals with the same energy levels to give a new degenerated type of orbitals. There are different types of hybridization namely: $sp,s{p}^2,s{p}^3,s{p}^{3}d$and $s{p}^3{d}^2$ .

Complete step by step answer:
-Hybridization can be defined as the mixing of two atomic orbitals with the same energy levels to give a new degenerated type of orbitals. There are different types of hybridization namely: $sp,s{p}^2,s{p}^3,s{p}^{3}d$ and $s{p}^3{d}^2$ .
-We will discuss about each hybridization as follows:
-$sp$ hybridization: In this type of hybridization, one $s$ orbital and one $p$ orbital are mixed together to form a completely new orbital called $sp$ orbital.
It forms linear molecules.
Example of $sp$ hybridization: $Be{F}_2,BeC{l}_2$ .
-$s{p}^2$ hybridization: In this type of hybridization, one $s$ orbital and two $p$ orbital are mixed together to form a completely new orbital called $s{p}^2$ orbital.
It forms a trigonal symmetry.
Example of $s{p}^2$ hybridization:$B{F}_3,B{H}_3$ .
-$s{p}^3$ hybridization: In this type of hybridization, one $s$ orbital and three $p$ orbital are mixed together to form a completely new orbital called $s{p}^3$ orbital.
It forms a tetrahedron.
Example of $s{p}^2$ hybridization: ethane,methane.
-$s{p}^{3}d$ hybridization: In this type of hybridization, one $s$ orbital , three $p$ orbital and one $d$ orbital are mixed together to form a completely new orbital called $s{p}^{3}d$orbital.
It forms a trigonal bipyramidal.
Example of $s{p}^2$hybridization: $PC{l}_5$
-$s{p}^{3}d$ hybridization: In this type of hybridization, one $s$ orbital , three $p$ orbital and two $d$ orbital are mixed together to form a completely new orbital called $s{p}^3{d}^2$orbital.
It forms an octahedron.
Now, we will discuss about the compound $buta-1,2-dien$ :
It is an organic compound and it is the isomer of $1,3-butadiene$ .
The structure of $buta-1,2-dien$ is given below:

It consists of two double bonds and two sigma bonds.
-$C{H}_2$ is attached to three atoms: two of hydrogen, one to carbon atom. Thus it is $s{p}^2$ hybridized.
-The carbon adjacent to the $C{H}_2$ group also has two double bonds which means it is $sp$ hybridized.
-The carbon that is attached to $C{H}_3$ is $s{p}^2$ hybridized because it is bonded to two carbon atoms and one hydrogen atom.
The carbon atom of $C{H}_3$ is $s{p}^3$ hybridized.

So the correct is option D) $sp$ , $s{p}^2$ and $s{p}^3$ hybridized carbon atoms.

Note:
The basic criteria to check for hybridisation of carbon atoms is to look at the number of bonds it has like if a carbon atom has triple bond it is sp hybridised , if it has double bond it is $s{p}^2$ hybridised and if a carbon atom has only single bonds it is $s{p}^3$ hybridised .