Answer
Verified
458.7k+ views
Hint: Here we should focus on the stability of carbocation, since when the above compounds will react with Lucas reagent, they will form a carbocation intermediate, and our aim is to select the most stable form of carbocation.
Complete step by step solution: Let's first decide on the stability of carbocation:
- Carbocation is classified as primary, secondary, or tertiary depending on one, two or three carbons directly attached to the positively charged carbon in the chain.
- So, the order of stability: primary carbocation < secondary carbocation < tertiary carbocation
Now let's briefly know the function of Lucas reagent:
- Alcohols at room temperature react with an equimolar mixture of concentrated hydrochloric acid and anhydrous zinc chloride to form alkyl halides, which is known as Lucas reagent.
- The equation is: $ROH+\underset{Conc.}{\mathop{HCl}}\,\xrightarrow{\text{Anhydrous ZnC}{{\text{l}}_{\text{2}}}}R-Cl+{{H}_{2}}O$
- On reacting with this reagent, an alkyl halide is formed.
- The rates of reaction by this reagent follow the following order: primary alcohol < secondary alcohol < tertiary alcohol
- As this stability order also depends on the degree of carbocation formed.
So, now let's look into the above question stated:
- The first option here is butan-1-ol, which is a primary alcohol, and forms a 1 degree carbocation, thus is not much stable.
- The second option has butan-2-ol, which forms secondary carbocation, and is more stable than primary one.
- The third option has 2-methylpropan-1-ol, this is also a primary alcohol, and forms a primary carbocation, and also does not react faster with Lucas reagent.
- But the fourth option has 2-methylpropan-2-ol, which forms a tertiary carbocation when reacts with Lucas reagent and thus is the most stable.
- So option D reacts fastest with the Lucas reagent and is the correct answer.
Additional Information: Now when the Lucas reagent is made to react with an unknown alcohol, the solution becomes cloudy before it separates as a distinct layer, and we can observe the following:
- If the turbidity (white) appears immediately, it's a tertiary alcohol.
- If turbidity appears within 5 minutes, it's a secondary alcohol.
- If the solution remains clear, and shows no turbidity, it's a primary alcohol.
Note: During the reaction of an alcohol with Lucas reagent, an alkyl halide is formed. So we need to check the type of carbocation intermediate formed during the reaction, when the hydroxyl group escapes out in the form of one water molecule and that will decide which alcohol will react fastest to form carbocation.
Complete step by step solution: Let's first decide on the stability of carbocation:
- Carbocation is classified as primary, secondary, or tertiary depending on one, two or three carbons directly attached to the positively charged carbon in the chain.
- So, the order of stability: primary carbocation < secondary carbocation < tertiary carbocation
Now let's briefly know the function of Lucas reagent:
- Alcohols at room temperature react with an equimolar mixture of concentrated hydrochloric acid and anhydrous zinc chloride to form alkyl halides, which is known as Lucas reagent.
- The equation is: $ROH+\underset{Conc.}{\mathop{HCl}}\,\xrightarrow{\text{Anhydrous ZnC}{{\text{l}}_{\text{2}}}}R-Cl+{{H}_{2}}O$
- On reacting with this reagent, an alkyl halide is formed.
- The rates of reaction by this reagent follow the following order: primary alcohol < secondary alcohol < tertiary alcohol
- As this stability order also depends on the degree of carbocation formed.
So, now let's look into the above question stated:
- The first option here is butan-1-ol, which is a primary alcohol, and forms a 1 degree carbocation, thus is not much stable.
- The second option has butan-2-ol, which forms secondary carbocation, and is more stable than primary one.
- The third option has 2-methylpropan-1-ol, this is also a primary alcohol, and forms a primary carbocation, and also does not react faster with Lucas reagent.
- But the fourth option has 2-methylpropan-2-ol, which forms a tertiary carbocation when reacts with Lucas reagent and thus is the most stable.
- So option D reacts fastest with the Lucas reagent and is the correct answer.
Additional Information: Now when the Lucas reagent is made to react with an unknown alcohol, the solution becomes cloudy before it separates as a distinct layer, and we can observe the following:
- If the turbidity (white) appears immediately, it's a tertiary alcohol.
- If turbidity appears within 5 minutes, it's a secondary alcohol.
- If the solution remains clear, and shows no turbidity, it's a primary alcohol.
Note: During the reaction of an alcohol with Lucas reagent, an alkyl halide is formed. So we need to check the type of carbocation intermediate formed during the reaction, when the hydroxyl group escapes out in the form of one water molecule and that will decide which alcohol will react fastest to form carbocation.
Recently Updated Pages
Identify the feminine gender noun from the given sentence class 10 english CBSE
Your club organized a blood donation camp in your city class 10 english CBSE
Choose the correct meaning of the idiomphrase from class 10 english CBSE
Identify the neuter gender noun from the given sentence class 10 english CBSE
Choose the word which best expresses the meaning of class 10 english CBSE
Choose the word which is closest to the opposite in class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Kaziranga National Park is famous for A Lion B Tiger class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write a letter to the principal requesting him to grant class 10 english CBSE