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The diameter of a sphere is decreased by 25%. By what percentage it’s curved surface area decrease?

Answer
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Hint – In this question use the concept that the new diameter of the sphere will be the old diameter subtracted with 25% of the old diameter. Then use the direct basic formula for curved surface area of the sphere which is S.A=4πr2 to obtain the % decrease in curved surface area.

Complete step-by-step answer:
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As we know that the curved surface area (S.A) of the sphere is (4πr2) where r is the radius of the sphere as shown in figure.
S.A=4πr2 Sq. unit. ................................... (1)
Now as we know radius (r) is half of the diameter (d).
r=d2 Unit.
Now substitute this value in equation (1) we have,
S.A=4π(d2)2=4πd24=πd2 Sq. unit.
Now it is given that the diameter of the sphere is decreased by 25%.
Therefore new diameter (d1) = old diameter (d) – 25% of old diameter (d).
d1=d25100d=3d4 Unit.
So the new surface area (S.A)1 of the sphere is
(S.A)1=π(3d4)2=916πd2 Sq. unit.
So the percentage decrease (% decrease) in surface area is the ratio of difference of old surface area and new surface area to old surface area multiplied by 100.
Therefore % decrease =πd2916πd2πd2×100
Now simplify the above equation we have,
Therefore % decrease =16πd29πd216πd2×100=716×100=43.75 %.
So the surface area of the sphere is decreased by 43.75%.
So this is the required answer.

Note – Let’s talk about why the question asked for a % decrease in curved surface area and not % increase when the diameter of the sphere is decreased. It’s because if diameter is decreased this means the sphere is shrinking now, and if it shrinks then eventually the curved surface area, volume and total surface area will decrease only.