The distance between Ahmedabad and Vadodara is 100 km. Two trains set-off simultaneously from Ahmedabad and Vadodara towards each other. The speeds of these trains are \[45\text{ }km/h\] and \[30\text{ }km/h\] respectively. When will they cross each other?
Answer
Verified
488.1k+ views
Hint: Since the value of speed of the train has been given and distance would be found out, therefore use the formula of speed which is distance per unit time. Since the time taken by both trains are the same. So equate both formulas of speed. Then calculate the value of distance where these two trains will cross each other.
Complete step-by-step answer:
Let, $ A $ be the train released from Ahmedabad having speed \[45\text{ }km/h\] and $ B $ be the train released from Vadodara having speed \[30\text{ }km/h\] .
Let, O be the point where the train will cross.
Let $ x $ be the distance from A to point O then $ 100-x $ will be the distance from B to O. Since the total distance between $ A\text{ and }B $ is \[100km\] .
If t be the time taken by both the train to reach at point O then
$ \text{speed}\left( \text{A} \right)=\dfrac{\text{distance}}{\text{time}\left( t \right)}\text{ }\!\!\And \!\!\text{ speed}\left( \text{B} \right)\text{=}\dfrac{\text{distance}}{\text{time}\left( t \right)} $
Put the values in both formulas. We get,
$ \begin{align}
& 45km/h=\dfrac{x}{t}\text{ }\!\!\And\!\!\text{ 30km/h=}\dfrac{100-x}{t} \\
& t=\dfrac{x}{45}\text{ }\!\!\And\!\!\text{ t=}\dfrac{100-x}{30} \\
\end{align} $
Now equate both equations. We get,
$ \begin{align}
& \dfrac{x}{45}=\dfrac{100-x}{30} \\
& 30x=4500-45x \\
& 75x=4500 \\
& x=60km \\
\end{align} $
So these two trains will cross each other a distance of 60km from $ A $ and $ 100-x=100-60=40km $ from $ B $.
Note: In this question, we have taken time for both the trains to cross each other is the same. Even though speed is different, time taken by trains will be different. Students may get confused like, velocity is different therefore time must be different but this is not always true. If speed of first body is greater than next then might be distance covered by first body will be more but time taken to reach at a point were both body will cross must be same.
Complete step-by-step answer:
Let, $ A $ be the train released from Ahmedabad having speed \[45\text{ }km/h\] and $ B $ be the train released from Vadodara having speed \[30\text{ }km/h\] .
Let, O be the point where the train will cross.
Let $ x $ be the distance from A to point O then $ 100-x $ will be the distance from B to O. Since the total distance between $ A\text{ and }B $ is \[100km\] .
If t be the time taken by both the train to reach at point O then
$ \text{speed}\left( \text{A} \right)=\dfrac{\text{distance}}{\text{time}\left( t \right)}\text{ }\!\!\And \!\!\text{ speed}\left( \text{B} \right)\text{=}\dfrac{\text{distance}}{\text{time}\left( t \right)} $
Put the values in both formulas. We get,
$ \begin{align}
& 45km/h=\dfrac{x}{t}\text{ }\!\!\And\!\!\text{ 30km/h=}\dfrac{100-x}{t} \\
& t=\dfrac{x}{45}\text{ }\!\!\And\!\!\text{ t=}\dfrac{100-x}{30} \\
\end{align} $
Now equate both equations. We get,
$ \begin{align}
& \dfrac{x}{45}=\dfrac{100-x}{30} \\
& 30x=4500-45x \\
& 75x=4500 \\
& x=60km \\
\end{align} $
So these two trains will cross each other a distance of 60km from $ A $ and $ 100-x=100-60=40km $ from $ B $.
Note: In this question, we have taken time for both the trains to cross each other is the same. Even though speed is different, time taken by trains will be different. Students may get confused like, velocity is different therefore time must be different but this is not always true. If speed of first body is greater than next then might be distance covered by first body will be more but time taken to reach at a point were both body will cross must be same.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE
What organs are located on the left side of your body class 11 biology CBSE