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The given figure consists of a square, a quarter circle and a semicircle. Area of sector is πr2θ360 . All the sides of a square are equal. Find the perimeter of the shaded portion.
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a)5πb)10πc)10(1+π)d)10(1π)

Answer
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Hint:In the figure we can see that the perimeter of the shaded portion is the addition of the circumference of quarter circle and semicircle. We know that circumference of a semicircle is 2πr2 and circumference of the quarter circle is 2πr4 . Now we can easily find the values of the two circumference and hence the required perimeter

Complete step by step answer:
Now consider the figure given
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We have two parts of circles here one with radius AB and another with diameter AB. We can see that the Perimeter of the shaded portion will be the addition of circumference of both radius.
Now consider the Quarter circle with a radius 10cm. Now we know that circumference of the quarter circle is given by 2πr4.
Now here the radius is AB, BC and is equal to 10cm hence we get
2π(10)4=20π4=5π
Hence we have the circumference of the quarter-circle that is arc AC is 5π........................(1)
Now consider the semicircle with diameter AB.
Now we know that circumference of the semicircle is given by 2πr2
Now we know that diameter = 2 × radius. Hence we have 2r = d
Substituting this we get
2πr2=πd2
Now we know that the diameter of the semicircle is AB and is equal to 10cm
Hence we get the circumference of the semicircle is
π(10)2=5π
Hence we have a circumference of a semicircle that is arc AB = 5π............................(2)
Now we know the perimeter of the shaded portion will be the addition to the circumference of both radii.
Hence from equation (1) and (2) we have
Perimeter of shaded portion is 5π+5π=10π
Hence we get the perimeter of the shaded portion is 10π.
Option b is the correct option.

Note:
Note that the area of circle is given by πr2 and circumference is given by 2πr . Also we have in general if the angle subtended by arc is θ then circumference of the arc is 2πr(θ)360 and similarly area of the part will be equal to πr2(θ)360

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