
The interior angles of a pentagon are in the ratio $2:3:4:5:6$ respectively, then what will be the sum of the first and the second angle?
A. ${90^0}$
B. ${140^0}$
C. ${135^0}$
D. ${180^0}$
Answer
618.6k+ views
Hint: We just have to generalize all the angles by multiplying them with a particular variable according to their ratio and equate their sum to the total sum of interior angles of a pentagon using the formula, Sum of interior angles of a regular pentagon $ = (n - 2) \times {180^0},$ where $n = 5$ for this equation i.e. number of sides of a regular pentagon due to which you will be able to find all the angles according to the generalized variable.
Complete step-by-step answer:
Let us suppose the angles of the pentagon are $2x,3x,4x,5x,$ and $6x$ according to the ratio given.
Let the number of sides of the pentagon be $n$
Now, we know that in a pentagon number of sides is equal to $n = 5$
We know that, in a regular pentagon, Sum of interior angles $ = (n - 2) \times {180^0}$
Substituting the value of $n = 5$ in the equation, we get
Sum of interior angles in a regular pentagon $ = (5 - 2) \times {180^0} = 3 \times {180^0} = {540^0}$
According to the question,
$2x + 3x + 4x + 5x + 6x = {540^0}$
$ \Rightarrow 20x = {540^0}$
$ \Rightarrow x = {27^0}$
Now, First angle $ = 2x = 2 \times {27^0} = {54^0}$ and Second angle $ = 3x = 3 \times {27^0} = {81^0}$
So, sum of the first and the second angle $ = {54^0} + {81^0} = {135^0}$
Hence, our required answer is ${135^0}$
Option C. is our correct answer
Note: Such type of questions can also be calculated by calculating the sum of the other three angles first and subtracting that from the ${540^0}$ due to which we will have to get the sum of the first and the second angle which we have been told to calculate.
Complete step-by-step answer:
Let us suppose the angles of the pentagon are $2x,3x,4x,5x,$ and $6x$ according to the ratio given.
Let the number of sides of the pentagon be $n$
Now, we know that in a pentagon number of sides is equal to $n = 5$
We know that, in a regular pentagon, Sum of interior angles $ = (n - 2) \times {180^0}$
Substituting the value of $n = 5$ in the equation, we get
Sum of interior angles in a regular pentagon $ = (5 - 2) \times {180^0} = 3 \times {180^0} = {540^0}$
According to the question,
$2x + 3x + 4x + 5x + 6x = {540^0}$
$ \Rightarrow 20x = {540^0}$
$ \Rightarrow x = {27^0}$
Now, First angle $ = 2x = 2 \times {27^0} = {54^0}$ and Second angle $ = 3x = 3 \times {27^0} = {81^0}$
So, sum of the first and the second angle $ = {54^0} + {81^0} = {135^0}$
Hence, our required answer is ${135^0}$
Option C. is our correct answer
Note: Such type of questions can also be calculated by calculating the sum of the other three angles first and subtracting that from the ${540^0}$ due to which we will have to get the sum of the first and the second angle which we have been told to calculate.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Difference Between Plant Cell and Animal Cell

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Which places in India experience sunrise first and class 9 social science CBSE

Who is eligible for RTE class 9 social science CBSE

What is pollution? How many types of pollution? Define it

Name 10 Living and Non living things class 9 biology CBSE


