Answer
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Hint: IUPAC stands for international union of pure and applied chemistry. It has made certain rules regarding the naming of organic compounds. The naming depends on the attached functional groups and the number of carbons in the parent chain, which is the longest chain.
Complete answer:
We have been given a structure to find its IUPAC name. We will determine the name through the rules of IUPAC. Some of the rules for IUPAC naming of organic compounds are:
- The functional group is identified, and named according to the specifications of the functional group, like, alkanoic acid for carboxylic acid group, alkanols for alcohols, alkyl alkanoate for esters, and alkoxy alkane for ethers, etc.
Here in the compound we have a carbon attached with two oxygen atoms, which means it is an ester with formula,$RCOO{{R}^{'}}$ , where R is the alkyl group.
- Now the chains are identified in the given compound.
On one side is the ethyl group, while on the other side of the ester is the 3 carbon chain with a methyl branch.
-The name of esters are given as alkyl alkanoate. So here it will be,
The compound has one ethyl chain so ethyl, and the 3 carbon chain has methyl on carbon- 2, so it will be 2 methyl propanoate.
Hence, the IUPAC name of the compound is ethyl-2-methyl propanoate.
So option B is correct.
Note:
In the case of oxygen containing organic compounds, the oxygen chain that is continuous and in the middle is considered a ester functional group. While it can be confused for the keto- carboxylic acids, which have a carbonyl group on beta carbon along with a carboxylic acid group at the end.
Complete answer:
We have been given a structure to find its IUPAC name. We will determine the name through the rules of IUPAC. Some of the rules for IUPAC naming of organic compounds are:
- The functional group is identified, and named according to the specifications of the functional group, like, alkanoic acid for carboxylic acid group, alkanols for alcohols, alkyl alkanoate for esters, and alkoxy alkane for ethers, etc.
Here in the compound we have a carbon attached with two oxygen atoms, which means it is an ester with formula,$RCOO{{R}^{'}}$ , where R is the alkyl group.
- Now the chains are identified in the given compound.
On one side is the ethyl group, while on the other side of the ester is the 3 carbon chain with a methyl branch.
-The name of esters are given as alkyl alkanoate. So here it will be,
The compound has one ethyl chain so ethyl, and the 3 carbon chain has methyl on carbon- 2, so it will be 2 methyl propanoate.
Hence, the IUPAC name of the compound is ethyl-2-methyl propanoate.
So option B is correct.
Note:
In the case of oxygen containing organic compounds, the oxygen chain that is continuous and in the middle is considered a ester functional group. While it can be confused for the keto- carboxylic acids, which have a carbonyl group on beta carbon along with a carboxylic acid group at the end.
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