
The length, breadth and height of a room are 5m, 4m and 3m respectively. Find out the cost of white washing the walls of the room and the ceiling at the rate of Rs. 7.50 per meter square.
Answer
522k+ views
Hint:
Find out the area of 4 walls and the ceiling individually. Add them together to get the total area. Then find out the costing for white wash.
Complete step-by-step answer:
Let $ABCD$ is the floor of a room. The length is $AB=CD=5m$ , breadth is $BC=CD=4m$ .
Height is 3m.
Now we have to find out the area of 4 walls.
Let us first find out the area of the wall which is perpendicular to the side $AB$.
For this wall the length is 5 meter, and the breadth is the height which is 3 meter.
We know that the area of a rectangle is = $length\times breadth$
So, the area of the wall which is perpendicular to the side $AB$ is:
$\begin{align}
&=\left( 5\times 3 \right){{m}^{2}} \\
&=15{{m}^{2}} \\
\end{align}$
The area of the wall which is perpendicular to the side $CD$ is basically the same as the area of the wall which is perpendicular to the side$AB$ . The length and the breadth, which is basically the height, are the same for both the walls.
Now the area of the wall which is perpendicular to the side $BC$ is:
$=\left( 4\times 3 \right){{m}^{2}}$
As the length of this wall is 4 meter and the breadth is 3 meter, which is the height.
So, the area is $=(4\times 3)=12{{m}^{2}}$
Similarly, the area of the wall which is perpendicular to the side $AD$ is basically the same as the area of the wall which is perpendicular to the side $BC$ . The length and the breadth, which is basically the height, are the same for both the walls.
Now, the total area of 4 walls is:
$=\left( 2\times 15 \right)+\left( 2\times 12 \right)=30+24=54{{m}^{2}}$
The area of the ceiling is the same as the floor.
So, the area of the ceiling is:
$=\left( 5\times 4 \right){{m}^{2}}=20{{m}^{2}}$
The total area is for white washing = total area of 4 walls + area of ceiling.
$\begin{align}
&=\left( 54+20 \right){{m}^{2}} \\
&=74{{m}^{2}} \\
\end{align}$
Now, the cost of white washing for one square meter is Rs. 7.50
The cost of white washing for 74 square meters is Rs.
$\begin{align}
&=74\times 7.50 \\
&=555 \\
\end{align}$
Therefore we need Rs. 555 to white wash the walls of the room and the ceiling.
Note: Alternatively we can directly use the area of four walls:
$=2\times \left( l+b \right)\times h$ , where $l$ is the length, $b$ is the breadth, $h$ is the height.
If we put the values in this formula:
$\begin{align}
& =2\times (5+4)\times 3=2\times 9\times 3 \\
& =54{{m}^{2}} \\
\end{align}$
So, the area of four walls is 54 square meters.
Find out the area of 4 walls and the ceiling individually. Add them together to get the total area. Then find out the costing for white wash.
Complete step-by-step answer:
Let $ABCD$ is the floor of a room. The length is $AB=CD=5m$ , breadth is $BC=CD=4m$ .
Height is 3m.

Now we have to find out the area of 4 walls.
Let us first find out the area of the wall which is perpendicular to the side $AB$.
For this wall the length is 5 meter, and the breadth is the height which is 3 meter.
We know that the area of a rectangle is = $length\times breadth$
So, the area of the wall which is perpendicular to the side $AB$ is:
$\begin{align}
&=\left( 5\times 3 \right){{m}^{2}} \\
&=15{{m}^{2}} \\
\end{align}$
The area of the wall which is perpendicular to the side $CD$ is basically the same as the area of the wall which is perpendicular to the side$AB$ . The length and the breadth, which is basically the height, are the same for both the walls.
Now the area of the wall which is perpendicular to the side $BC$ is:
$=\left( 4\times 3 \right){{m}^{2}}$
As the length of this wall is 4 meter and the breadth is 3 meter, which is the height.
So, the area is $=(4\times 3)=12{{m}^{2}}$
Similarly, the area of the wall which is perpendicular to the side $AD$ is basically the same as the area of the wall which is perpendicular to the side $BC$ . The length and the breadth, which is basically the height, are the same for both the walls.
Now, the total area of 4 walls is:
$=\left( 2\times 15 \right)+\left( 2\times 12 \right)=30+24=54{{m}^{2}}$
The area of the ceiling is the same as the floor.
So, the area of the ceiling is:
$=\left( 5\times 4 \right){{m}^{2}}=20{{m}^{2}}$
The total area is for white washing = total area of 4 walls + area of ceiling.
$\begin{align}
&=\left( 54+20 \right){{m}^{2}} \\
&=74{{m}^{2}} \\
\end{align}$
Now, the cost of white washing for one square meter is Rs. 7.50
The cost of white washing for 74 square meters is Rs.
$\begin{align}
&=74\times 7.50 \\
&=555 \\
\end{align}$
Therefore we need Rs. 555 to white wash the walls of the room and the ceiling.
Note: Alternatively we can directly use the area of four walls:
$=2\times \left( l+b \right)\times h$ , where $l$ is the length, $b$ is the breadth, $h$ is the height.
If we put the values in this formula:
$\begin{align}
& =2\times (5+4)\times 3=2\times 9\times 3 \\
& =54{{m}^{2}} \\
\end{align}$
So, the area of four walls is 54 square meters.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Truly whole mankind is one was declared by the Kannada class 10 social science CBSE

Explain the three major features of the shiwaliks class 10 social science CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

What are the public facilities provided by the government? Also explain each facility

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Question An example of homologous organs is a Our arm class 10 biology CBSE
