The line joining the points \[{\text{(}} - {\text{6}},8{\text{)}}\] and \[{\text{(8,}} - {\text{6)}}\] is divided into four equal parts; find the coordinates of the points of section.
Answer
Verified
509.4k+ views
Hint: - Here, we use bisector formulas to find midpoints.
Let \[{\text{A(}} - {\text{6,8)}}\] and \[{\text{B(8,}} - {\text{6)}}\] and \[{\text{P,Q,R}}\] divides \[{\text{AB}}\] in four equal parts \[{\text{Q}}\] divides \[{\text{AB}}\] in \[{\text{1:1}}\],so \[{\text{Q}}\] is the midpoint of \[{\text{AB}}\].
So coordinates of \[{\text{Q}}\] are \[\dfrac{{ - {\text{6 + 8}}}}{2}{\text{,}}\dfrac{{{\text{8}} - {\text{6}}}}{2}\]
\[ \Rightarrow {\text{Q}}(1,1)\]
Similarly ${\text{P}}$ is the midpoint of \[{\text{AQ}}\]
So coordinates of ${\text{P }}$ are \[\dfrac{{ - {\text{6 + 1}}}}{2},\dfrac{{8+1}}{2}\]
\[ \Rightarrow {\text{P}}\left( { - \dfrac{5}{2},\dfrac{9}{2}} \right)\]
And now \[{\text{R }}\] is the midpoint of ${\text{QB}}$
So coordinates of \[{\text{R}}\] are \[\dfrac{{1 + 8}}{2},\dfrac{{1 - 6}}{2}\]
\[ \Rightarrow {\text{R }}\left( {\dfrac{9}{2},\dfrac{{ - 5}}{2}} \right)\]
The points which divide the line in four equal parts are \[\left( { - \dfrac{5}{2},\dfrac{9}{2}} \right);(1,1);\left( {\dfrac{9}{2},\dfrac{{ - 5}}{2}} \right)\]
Note:-Whenever we face such types of questions it is better to denote the coordinate by letter and then bisect the first line and after that bisect that line. Which are made by the bisector of the first line.
Let \[{\text{A(}} - {\text{6,8)}}\] and \[{\text{B(8,}} - {\text{6)}}\] and \[{\text{P,Q,R}}\] divides \[{\text{AB}}\] in four equal parts \[{\text{Q}}\] divides \[{\text{AB}}\] in \[{\text{1:1}}\],so \[{\text{Q}}\] is the midpoint of \[{\text{AB}}\].
So coordinates of \[{\text{Q}}\] are \[\dfrac{{ - {\text{6 + 8}}}}{2}{\text{,}}\dfrac{{{\text{8}} - {\text{6}}}}{2}\]
\[ \Rightarrow {\text{Q}}(1,1)\]
Similarly ${\text{P}}$ is the midpoint of \[{\text{AQ}}\]
So coordinates of ${\text{P }}$ are \[\dfrac{{ - {\text{6 + 1}}}}{2},\dfrac{{8+1}}{2}\]
\[ \Rightarrow {\text{P}}\left( { - \dfrac{5}{2},\dfrac{9}{2}} \right)\]
And now \[{\text{R }}\] is the midpoint of ${\text{QB}}$
So coordinates of \[{\text{R}}\] are \[\dfrac{{1 + 8}}{2},\dfrac{{1 - 6}}{2}\]
\[ \Rightarrow {\text{R }}\left( {\dfrac{9}{2},\dfrac{{ - 5}}{2}} \right)\]
The points which divide the line in four equal parts are \[\left( { - \dfrac{5}{2},\dfrac{9}{2}} \right);(1,1);\left( {\dfrac{9}{2},\dfrac{{ - 5}}{2}} \right)\]
Note:-Whenever we face such types of questions it is better to denote the coordinate by letter and then bisect the first line and after that bisect that line. Which are made by the bisector of the first line.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE
Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE
With reference to graphite and diamond which of the class 11 chemistry CBSE
A certain household has consumed 250 units of energy class 11 physics CBSE
The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE
What is the formula mass of the iodine molecule class 11 chemistry CBSE
Trending doubts
The reservoir of dam is called Govind Sagar A Jayakwadi class 11 social science CBSE
What problem did Carter face when he reached the mummy class 11 english CBSE
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
In China rose the flowers are A Zygomorphic epigynous class 11 biology CBSE
What is Environment class 11 chemistry CBSE
Nucleolus is present in which part of the cell class 11 biology CBSE