Answer
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Hint- In order to calculate the mass of one atom of carbon in gram first we will use the atomic mass of carbon. As we know that atomic mass is given for one mole of atom so by dividing the mass of one mole of carbon atoms by Avagadro’s number we will find the mass of one atom of carbon.
Complete answer:
Formula used- ${\text{mass of one atom}} = \dfrac{{{\text{Atomic mass}}}}{{{\text{Avagadro number}}}}$
Atomic weight of one carbon atom = 12amu
Mass of 1 mole of carbon atoms = 1 × atomic weight of one carbon
=12 gm
As we know that that atomic mass is given for one mole of atom so by dividing the mass by Avagadro’s number we will find the mass of one atom.
Mass of one atom of carbon is:
\[
= \dfrac{{{\text{Atomic mass}}}}{{{\text{Avagadro number}}}} \\
= \dfrac{{12g}}{{{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}}} \\
= \dfrac{{12}}{{{\text{6}}{\text{.022}}}} \times {\text{1}}{{\text{0}}^{ - 23}}g \\
= 1.9933 \times {\text{1}}{{\text{0}}^{ - 23}}g \\
\]
Hence, the mass of 1 carbon atom is $1.9933 \times {\text{1}}{{\text{0}}^{ - 23}}gram$
Note- Molar mass is the mass of Avogadro's number of atoms of that element or compound. Avogadro's number is $6.022 \times {10^{23}}$ and can be used to represent the number of representative particles of any particle on the atomic scale. The molar masses of the elements are listed on the periodic table. In order to solve such types of problems students must remember the formula for molecular weight and must know the method to find the atomic weight of any compound.
Complete answer:
Formula used- ${\text{mass of one atom}} = \dfrac{{{\text{Atomic mass}}}}{{{\text{Avagadro number}}}}$
Atomic weight of one carbon atom = 12amu
Mass of 1 mole of carbon atoms = 1 × atomic weight of one carbon
=12 gm
As we know that that atomic mass is given for one mole of atom so by dividing the mass by Avagadro’s number we will find the mass of one atom.
Mass of one atom of carbon is:
\[
= \dfrac{{{\text{Atomic mass}}}}{{{\text{Avagadro number}}}} \\
= \dfrac{{12g}}{{{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}}} \\
= \dfrac{{12}}{{{\text{6}}{\text{.022}}}} \times {\text{1}}{{\text{0}}^{ - 23}}g \\
= 1.9933 \times {\text{1}}{{\text{0}}^{ - 23}}g \\
\]
Hence, the mass of 1 carbon atom is $1.9933 \times {\text{1}}{{\text{0}}^{ - 23}}gram$
Note- Molar mass is the mass of Avogadro's number of atoms of that element or compound. Avogadro's number is $6.022 \times {10^{23}}$ and can be used to represent the number of representative particles of any particle on the atomic scale. The molar masses of the elements are listed on the periodic table. In order to solve such types of problems students must remember the formula for molecular weight and must know the method to find the atomic weight of any compound.
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