The mass of the earth is $6 \times {10^{24}}$ kg and that of the moon is $7.4 \times {10^{22}}$ kg. If the distance between the earth and the moon is $3.84 \times {10^5}$ km, calculate the force exerted by the earth on the moon. Consider $G = 6.7 \times {10^{ - 11}}{\text{N}}{{\text{m}}^{\text{2}}}{\text{k}}{{\text{g}}^{{\text{ - 2}}}}$.
Answer
624.9k+ views
Hint
Newton's universal law of gravitation can be used to find the gravitational force between any two objects. This force depends on the mass of the objects involved and the distance between them.
$\Rightarrow F = G\dfrac{{Mm}}{{{r^2}}}$ where $F$ is the force of attraction between two objects of mass $M$and $m$, separated by a distance $r$. $G$ is the universal gravitational constant.
Complete step by step answer
The two bodies specified in the question are the Earth and the moon. We are asked to find the force exerted by the Earth on the moon. The data provided to us include:
Mass of the Earth $M = 6 \times {10^{24}}$kg
Mass of the moon $m = 7.4 \times {10^{22}}$kg
Distance between the two $r = 3.84 \times {10^5}$ km $ = 3.84 \times {10^8}$ m [As 1 km = 1000 m]
Gravitational constant $G = 6.7 \times {10^{ - 11}}{\text{N}}{{\text{m}}^{\text{2}}}{\text{k}}{{\text{g}}^{{\text{ - 2}}}}$
We are aware that the force between two gravitationally bound objects can be found by applying Newton’s Law as:
$\Rightarrow F = G\dfrac{{Mm}}{{{r^2}}}$
Substituting the given values in this equation gives us:
$\Rightarrow F = 6.7 \times {10^{ - 11}}\dfrac{{6 \times {{10}^{24}} \times 7.4 \times {{10}^{22}}}}{{{{(3.84 \times {{10}^8})}^2}}}$
Expanding the square term and cancelling all the powers of 10 gives us:
$\Rightarrow F = \dfrac{{6.7 \times 6 \times 7.4 \times {{10}^{35}}}}{{14.7456 \times {{10}^{16}}}} = \dfrac{{297.48}}{{14.746}} \times {10^{19}}$
This gives us the force between the two as:
$\Rightarrow F = 20.17 \times {10^{19}}$ N
Note
In the question we were asked to find the force exerted by the Earth on the moon, but this is also equal to the force exerted by the moon on Earth. Newton’s third law of motion states that every force has an equal and opposite reaction. That is why there is no distinction between equations when trying to find the force, and just one equation is valid no matter which body exerts force on the other.
Newton's universal law of gravitation can be used to find the gravitational force between any two objects. This force depends on the mass of the objects involved and the distance between them.
$\Rightarrow F = G\dfrac{{Mm}}{{{r^2}}}$ where $F$ is the force of attraction between two objects of mass $M$and $m$, separated by a distance $r$. $G$ is the universal gravitational constant.
Complete step by step answer
The two bodies specified in the question are the Earth and the moon. We are asked to find the force exerted by the Earth on the moon. The data provided to us include:
Mass of the Earth $M = 6 \times {10^{24}}$kg
Mass of the moon $m = 7.4 \times {10^{22}}$kg
Distance between the two $r = 3.84 \times {10^5}$ km $ = 3.84 \times {10^8}$ m [As 1 km = 1000 m]
Gravitational constant $G = 6.7 \times {10^{ - 11}}{\text{N}}{{\text{m}}^{\text{2}}}{\text{k}}{{\text{g}}^{{\text{ - 2}}}}$
We are aware that the force between two gravitationally bound objects can be found by applying Newton’s Law as:
$\Rightarrow F = G\dfrac{{Mm}}{{{r^2}}}$
Substituting the given values in this equation gives us:
$\Rightarrow F = 6.7 \times {10^{ - 11}}\dfrac{{6 \times {{10}^{24}} \times 7.4 \times {{10}^{22}}}}{{{{(3.84 \times {{10}^8})}^2}}}$
Expanding the square term and cancelling all the powers of 10 gives us:
$\Rightarrow F = \dfrac{{6.7 \times 6 \times 7.4 \times {{10}^{35}}}}{{14.7456 \times {{10}^{16}}}} = \dfrac{{297.48}}{{14.746}} \times {10^{19}}$
This gives us the force between the two as:
$\Rightarrow F = 20.17 \times {10^{19}}$ N
Note
In the question we were asked to find the force exerted by the Earth on the moon, but this is also equal to the force exerted by the moon on Earth. Newton’s third law of motion states that every force has an equal and opposite reaction. That is why there is no distinction between equations when trying to find the force, and just one equation is valid no matter which body exerts force on the other.
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Draw a diagram showing the external features of fish class 11 biology CBSE

