
The mass of the moon is about $0.013$ times the mass of the earth and the distance from the center of mass to the center of the earth is about $60$ times the radius of the earth. Show that the center of mass of the earth-moon system lies inside the earth and find its approximation from the center of the earth. Take the earth’s radius to be $6400\text{ km}$.
Answer
516.6k+ views
Hint: Center of mass of a system can be defined as the point at which we can concentrate all the mass of the system. To solve these types of questions, we must have knowledge about the formula used to calculate the center of mass of a system using the mass of the system and distance of the bodies in the system from the center of mass.
Complete step-by-step solution: -
Let us assume the mass of earth to be $m\text{ kg}$, then the mass of the moon which is about $0.013$ times the mass of the earth would be $0.013m$. Let us consider that the center of the earth lies at origin. Then the distance of the moon from the center of the earth which is given to be about $60$ times the radius of the earth will be $60R$, where $R$is the radius of the earth.
The center of mass of the earth-moon system can be found out with the following formula:
$CM=\dfrac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
On substituting the values in the formula, we get:
\[\begin{align}
& CM=\dfrac{m\times 0+0.013m\times 60R}{m+0.013m} \\
& \Rightarrow CM=\dfrac{0.78mR}{1.013m} \\
& \Rightarrow CM=\dfrac{0.78R}{1.013} \\
& \Rightarrow CM=0.76999R \\
\end{align}\]
Hence, it is proved that the center of mass of the earth-moon system lies inside the earth.
We know that the radius of earth is given as $6400\text{ km}$, hence on substituting the value in the equation, we get:
$\begin{align}
& CM=0.76999\times 6400 \\
& \Rightarrow CM=\text{4927}\text{.936 km} \\
& \therefore CM\approx \text{4928 km} \\
\end{align}$
Thus, the approximate value of the distance of center of mass of the earth-moon system from the center of earth comes out to be $4928\text{ km}$.
Note: We must keep in mind that the center of mass of a system will always lie inside the system. It can be defined as that point which can be assumed to carry all the mass of the system. It must not be confused with center of gravity as these two terms are quite different.
Complete step-by-step solution: -
Let us assume the mass of earth to be $m\text{ kg}$, then the mass of the moon which is about $0.013$ times the mass of the earth would be $0.013m$. Let us consider that the center of the earth lies at origin. Then the distance of the moon from the center of the earth which is given to be about $60$ times the radius of the earth will be $60R$, where $R$is the radius of the earth.
The center of mass of the earth-moon system can be found out with the following formula:
$CM=\dfrac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
On substituting the values in the formula, we get:
\[\begin{align}
& CM=\dfrac{m\times 0+0.013m\times 60R}{m+0.013m} \\
& \Rightarrow CM=\dfrac{0.78mR}{1.013m} \\
& \Rightarrow CM=\dfrac{0.78R}{1.013} \\
& \Rightarrow CM=0.76999R \\
\end{align}\]
Hence, it is proved that the center of mass of the earth-moon system lies inside the earth.
We know that the radius of earth is given as $6400\text{ km}$, hence on substituting the value in the equation, we get:
$\begin{align}
& CM=0.76999\times 6400 \\
& \Rightarrow CM=\text{4927}\text{.936 km} \\
& \therefore CM\approx \text{4928 km} \\
\end{align}$
Thus, the approximate value of the distance of center of mass of the earth-moon system from the center of earth comes out to be $4928\text{ km}$.
Note: We must keep in mind that the center of mass of a system will always lie inside the system. It can be defined as that point which can be assumed to carry all the mass of the system. It must not be confused with center of gravity as these two terms are quite different.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

