Answer
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Hint: For solving this question, first we have to find the ratio of (No. of moles of $NaCl$) to (No of moles of whole solution). And then we have to use the formula for calculating mole fraction i.e;
Mole fraction=$\dfrac{{no.\,of\,moles\,of\,NaCl}}{{no.\,of\,moles\,of\,Solution}}$
Complete step-by-step answer:
No. of moles of ${H_2}O$ = \[\dfrac{{Weight}}{{Molecular.Mass}}\] =$\dfrac{{1000}}{{18}}$ =55.55
No. of moles of NaCl= 1
Mole fraction of NaCl=$\dfrac{{no.\,of\,moles\,of\,NaCl}}{{no.\,of\,moles\,of\,NaCl + no.\,of\,moles\,of\,{H_2}O}}$
=$\dfrac{1}{{55.55 + 1}}$
=0.01768$ \approx $ 0.0177
Thus option A “0.0177” is the correct answer to the problem.
Note: For solving this question, one should know the molecular mass of an element and should also know how to calculate the no. of moles.
Mole fraction=$\dfrac{{no.\,of\,moles\,of\,NaCl}}{{no.\,of\,moles\,of\,Solution}}$
Complete step-by-step answer:
No. of moles of ${H_2}O$ = \[\dfrac{{Weight}}{{Molecular.Mass}}\] =$\dfrac{{1000}}{{18}}$ =55.55
No. of moles of NaCl= 1
Mole fraction of NaCl=$\dfrac{{no.\,of\,moles\,of\,NaCl}}{{no.\,of\,moles\,of\,NaCl + no.\,of\,moles\,of\,{H_2}O}}$
=$\dfrac{1}{{55.55 + 1}}$
=0.01768$ \approx $ 0.0177
Thus option A “0.0177” is the correct answer to the problem.
Note: For solving this question, one should know the molecular mass of an element and should also know how to calculate the no. of moles.
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