Question

The number of lines of symmetry in a parallelogram are
$$\begin{gathered} \text{A}\text{. one} \\ \text{B}\text{. zero} \\ \text{C}\text{. two} \\ \text{D}\text{. four} \end{gathered}$$

Answer 1

Hint:We should have knowledge of lines of symmetry because then only we can check how many lines of symmetry present in a parallelogram. Here we have to think about general parallelogram not about type of parallelogram.

Complete step-by-step solution:
Lines of symmetry: we say there is symmetry when the exact reflection of the mirror image of a line, shape or object gets created. The line of symmetry can be defined as the axis or imaginary line that passes through the center of the shape or the object and divides into identical halves.
Here option B is the correct option.
Because A general parallelogram has no lines of symmetry. Some special ones (rhombus, rectangle, square) have lines of symmetry. However, a parallelogram does not have a crucial symmetry – the half-turn around the central point where the two diagonals intersect.

Note: Whenever you get this type of question the key concept of solving is you have to consider general parallelogram not any special one and by drawing a line we have to check that it has a line of symmetry or not.