Answer
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Hint: We will first list out the numbers between 38 and 68 . Then from the definition of the whole number we will segregate the numbers. We will then count them and find the number of whole numbers between 38 and 68.
Complete step-by-step solution:
Whole numbers are the numbers starting from 0 and all counting numbers are included in whole numbers .
Whole numbers are from 0 to infinity.
The whole numbers from 38 and 68 :
38 , 39 , 40 , 41 , 42 , 43 , 44 , 45 , 46 , 47 , 48 , 49 , 50 , 51 , 52 , 53 , 54 , 55 , 56 , 57 , 58 ,59 ,60 , 61 , 62 , 63 , 64 , 65 , 66 , 67 , 68 .
Let us count these numbers. There 29 numbers between 38 and 68 .
Hence the number of whole numbers between 38 and 68 are 29 .
Note: This problem can be solved by using a formula . The number of whole numbers between m and n ($m < n$) is $(m - n) - 1$. Now let us substitute the values of numbers given in question , that is
$ m - n - 1 = 68 - 38 - 1 \\
= 30 - 1 \\
= 29 $
Therefore, the number of whole numbers between 38 and 68 are 29 . The word ‘between’ in the question does not include the numbers m and n . This is the simplest approach for this question.
Complete step-by-step solution:
Whole numbers are the numbers starting from 0 and all counting numbers are included in whole numbers .
Whole numbers are from 0 to infinity.
The whole numbers from 38 and 68 :
38 , 39 , 40 , 41 , 42 , 43 , 44 , 45 , 46 , 47 , 48 , 49 , 50 , 51 , 52 , 53 , 54 , 55 , 56 , 57 , 58 ,59 ,60 , 61 , 62 , 63 , 64 , 65 , 66 , 67 , 68 .
Let us count these numbers. There 29 numbers between 38 and 68 .
Hence the number of whole numbers between 38 and 68 are 29 .
Note: This problem can be solved by using a formula . The number of whole numbers between m and n ($m < n$) is $(m - n) - 1$. Now let us substitute the values of numbers given in question , that is
$ m - n - 1 = 68 - 38 - 1 \\
= 30 - 1 \\
= 29 $
Therefore, the number of whole numbers between 38 and 68 are 29 . The word ‘between’ in the question does not include the numbers m and n . This is the simplest approach for this question.
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