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Hint: When a cross is carried out between round- shaped yellow color seeds (RRYY) and wrinkled shape green color seeds (rryy) it is a dihybrid cross as two characters are taken at a single time in a single cross. According to Mendel's law of independent assortment, when two characters are observed in a single cross both the characters separate independently from one another.
Complete step by step answer:
When Mendel crossed yellow colored round shape seeds (RRYY) with green colored wrinkled shape seeds (rryy) he observed a phenotypic ratio of 9:3:3:1 (i.e., 9 round yellow seeds, 3 round green seeds, 3 yellow wrinkled seeds, and 1 green wrinkled seeds). In the F2 generation,
(i) heterozygous for both shape and color of seeds (RrYy) is 4 numbers.
(ii) dominant for color, but recessive for shape (rrYY/rrYy) is 3 numbers.
(iii) homozygous for both the shape and color of seeds (RRYY/rryy) is 2 numbers.
(iv) heterozygous for seed shape only (Rryy/RrYY) is 8 numbers
So, the correct answer is `i - 4, ii - 2, iii - 3, and iv - 8`.
Additional information:
- When round yellow seeds (RRYY) are crossed with wrinkled green seeds (rryy) in filial 1 generation we obtain a progeny of RrYy i.e., round yellow seeds. When F1 progeny undergoes self cross, in F2 generation we obtain a progeny in the ratio of 9 (round, yellow seeds) : 3 (yellow, wrinkled) : 3 (green, round) : 1 (green, wrinkled).
- Characters separate independently of one another, and thus shape and color of seeds characters separate independently.
- Exception to the law of independent assortment is found incomplete dominance (when the dominant gene does not completely mask the effect of the recessive gene and thus the phenotypic appearance shows a blending of both) and codominance (when both the alleles express themselves equally).
Note: Mendel gave his first two laws- the law of dominance and law of segregation with respect to monohybrid cross and the third law- the law of independent assortment with respect to dihybrid cross. This law was given by Mendel in 1865. The genotypic ratio shown by this cross is 1:2:1:2:4:2:1:2:1.
Complete step by step answer:
When Mendel crossed yellow colored round shape seeds (RRYY) with green colored wrinkled shape seeds (rryy) he observed a phenotypic ratio of 9:3:3:1 (i.e., 9 round yellow seeds, 3 round green seeds, 3 yellow wrinkled seeds, and 1 green wrinkled seeds). In the F2 generation,
(i) heterozygous for both shape and color of seeds (RrYy) is 4 numbers.
(ii) dominant for color, but recessive for shape (rrYY/rrYy) is 3 numbers.
(iii) homozygous for both the shape and color of seeds (RRYY/rryy) is 2 numbers.
(iv) heterozygous for seed shape only (Rryy/RrYY) is 8 numbers
So, the correct answer is `i - 4, ii - 2, iii - 3, and iv - 8`.
Additional information:
- When round yellow seeds (RRYY) are crossed with wrinkled green seeds (rryy) in filial 1 generation we obtain a progeny of RrYy i.e., round yellow seeds. When F1 progeny undergoes self cross, in F2 generation we obtain a progeny in the ratio of 9 (round, yellow seeds) : 3 (yellow, wrinkled) : 3 (green, round) : 1 (green, wrinkled).
- Characters separate independently of one another, and thus shape and color of seeds characters separate independently.
- Exception to the law of independent assortment is found incomplete dominance (when the dominant gene does not completely mask the effect of the recessive gene and thus the phenotypic appearance shows a blending of both) and codominance (when both the alleles express themselves equally).
Note: Mendel gave his first two laws- the law of dominance and law of segregation with respect to monohybrid cross and the third law- the law of independent assortment with respect to dihybrid cross. This law was given by Mendel in 1865. The genotypic ratio shown by this cross is 1:2:1:2:4:2:1:2:1.
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