
The radius of the circle is 15 cm and the length of one of the chords is 18cm. Find the distance of the chord from the centre.
Answer
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Hint: Draw a perpendicular from the center to the chord of the circle and use the property of the circle that says a perpendicular drawn from the centre of the circle to the chord bisects the chord.
Complete step-by-step answer:
Let AB=18cm is the chord of the circle as given in the question
And OB=15cm is the radius of the circle.
Let OM be a perpendicular drawn from the centre of the circle to the chord.
Let OM=x cm
Since the perpendicular drawn on a chord from the centre of the circle bisects the chord (property of a circle)
MB=9cm
Thus in the right angled triangle OMB,
Using Pythagoras theorem we get,
Thus the distance of the chord from the center of the circle is 12cm.
Note: It is very important in such questions to realize that we have to draw a perpendicular from the centre to the chord or else the property will not be applicable.
No right angled triangle is formed in such a case and hence is difficult to solve the question.
Complete step-by-step answer:

Let AB=18cm is the chord of the circle as given in the question
And OB=15cm is the radius of the circle.
Let OM be a perpendicular drawn from the centre of the circle to the chord.
Let OM=x cm
Since the perpendicular drawn on a chord from the centre of the circle bisects the chord (property of a circle)
Thus in the right angled triangle OMB,
Using Pythagoras theorem we get,
Thus the distance of the chord from the center of the circle is 12cm.
Note: It is very important in such questions to realize that we have to draw a perpendicular from the centre to the chord or else the property will not be applicable.

No right angled triangle is formed in such a case and hence is difficult to solve the question.
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