Answer
Verified
444.3k+ views
Hint- Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
$E \propto {T^4}$
Here, $T$ is the temperature of the black body.
Step by step solution:
Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
$E \propto {T^4}$
Or
$E = \sigma {T^4}$
Where, $\sigma $ is the Stefan’s constant and $T$ is the temperature.
Given,
Temperature,
$
{T_1} = {273^ \circ }C \\
= 273 + 273\,K \\
= 556\,K \\
$
Let the rate of emission of radiation of black body at ${273^ \circ }C$ be denoted as ${E_1}$.
Therefore, using Stefan’s law, we can write,
${E_1} = \sigma {T_1}^4$ ……. (1)
Temperature,
$
{T_2} = {0^ \circ }C \\
= 0 + 273\,K \\
= 273\,K \\
$
Let the rate of emission of radiation of black body at ${0^ \circ }C$ be denoted as ${E_2}$.
Therefore, using Stefan’s law, we can write,
${E_2} = \sigma {T_2}^4$ …… (2)
Divide equation (1) by (2). Then, we get
\[
\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{T_1}^4}}{{{T_2}^4}} \\
\dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{{T_1}}}{{{T_2}}}} \right)^4} \\
\]
Now substitute the given values. Then, we get
\[
\dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{556}}{{273}}} \right)^4} \\
= {\left( 2 \right)^4} \\
= 16 \\
\]
That is,
${E_2} = \dfrac{{{E_1}}}{{16}}$
Hence the correct answer is option A.
Note: Remember to convert the temperatures given in $^ \circ C$ into the corresponding temperature in kelvin.
Formula to remember
Stefan’s law, $E = \sigma {T^4}$
Where, $E$ is the total power radiated per unit surface area of a black body and $T$ is the temperature of black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
$E \propto {T^4}$
Here, $T$ is the temperature of the black body.
Step by step solution:
Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
$E \propto {T^4}$
Or
$E = \sigma {T^4}$
Where, $\sigma $ is the Stefan’s constant and $T$ is the temperature.
Given,
Temperature,
$
{T_1} = {273^ \circ }C \\
= 273 + 273\,K \\
= 556\,K \\
$
Let the rate of emission of radiation of black body at ${273^ \circ }C$ be denoted as ${E_1}$.
Therefore, using Stefan’s law, we can write,
${E_1} = \sigma {T_1}^4$ ……. (1)
Temperature,
$
{T_2} = {0^ \circ }C \\
= 0 + 273\,K \\
= 273\,K \\
$
Let the rate of emission of radiation of black body at ${0^ \circ }C$ be denoted as ${E_2}$.
Therefore, using Stefan’s law, we can write,
${E_2} = \sigma {T_2}^4$ …… (2)
Divide equation (1) by (2). Then, we get
\[
\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{T_1}^4}}{{{T_2}^4}} \\
\dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{{T_1}}}{{{T_2}}}} \right)^4} \\
\]
Now substitute the given values. Then, we get
\[
\dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{556}}{{273}}} \right)^4} \\
= {\left( 2 \right)^4} \\
= 16 \\
\]
That is,
${E_2} = \dfrac{{{E_1}}}{{16}}$
Hence the correct answer is option A.
Note: Remember to convert the temperatures given in $^ \circ C$ into the corresponding temperature in kelvin.
Formula to remember
Stefan’s law, $E = \sigma {T^4}$
Where, $E$ is the total power radiated per unit surface area of a black body and $T$ is the temperature of black body.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
What percentage of the solar systems mass is found class 8 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Why is there a time difference of about 5 hours between class 10 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE