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The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement(s) is(are) correct?
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[This question has multiple correct options]
(A) T1=T2
(B) T3>T1
(C) wisothermal>wadiabatic
(D) ΔUisothermal>ΔUadiabatic

Answer
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Hint: Isothermal process is a process in which the temperature remains the same throughout the process. So, ΔT=0. In adiabatic processes, the heat of the system remains constant, so ΔQ=0 .

Complete answer:
We will find which of the statements are wrong as given in the graph.
- Isothermal process is a process in which the temperature remains the same throughout the process. In the isothermal curve, we can see that the initial temperature is T1 and the final temperature is T2. We know that as the process is isothermal, the temperature will not change. Thus, we can say that T1=T2.
- In adiabatic processes, the heat of the system remains constant. So, in this process, we can say that the initial temperature is shown as T1 in the adiabatic curve. The final temperature is T3. We can say that the final temperature is lower than the initial temperature from the curve. Thus, T1>T3.
- In the isothermal process, we know that ΔUisothermal is zero. Thus, we can say that this energy gets converted into work (wisothermal) done. For adiabatic process, Q = 0. Thus, we can say that the work done by the isothermal process will be higher than the adiabatic process. So, wisothermal>wadiabatic
- We have seen earlier that the change in internal energy in isothermal energy is zero. Thus, ΔUisothermal=0 . But in adiabatic processes, the work done is always negative. So, we can say that ΔUisothermal>ΔUadiabatic

Thus, we can conclude that options (A), (C) and (D) are correct.

Note:
Remember that a process can be called reversible if the change is brought in such a way that it can be reversed by a change. It involves equilibrium states in it. The processes that are not reversible are called irreversible processes.