Answer
Verified
458.7k+ views
Hint: The area under enclosed by the graph formed between the quantities ${E_\lambda }$and $\lambda $ denotes the total emissive power radiated by the body. And total emissive power radiated by a body can be calculated by stefan’s law, $E = e\sigma {T^4}$, where E denotes total emissive power, e denotes emissivity of the body, σ is the stefan’s constant and T denotes absolute temperature of the body. The wavelength at which spectral emissive power is maximum relates to the temperature according to wein’s displacement law i.e. ${\lambda _1}{T_1} = {\lambda _2}{T_2}$ .
Complete step by step solution:
The total area under the graph formed between the quantities ${E_\lambda }$ and $\lambda $ denotes total emissive power radiated by a body.
Given that total emissive power at temperature T1 is A,
Using Stefan's law we can say that : $A = e\sigma {T_1}^4$ .
Given that total emissive power at temperature T2 is 9A,
Using Stefan's law we can say that $9A = \sigma {T_2}^4$.
Dividing these two equations, we get :
\[\dfrac{A}{{9A}} = \dfrac{{\sigma {T_1}^4}}{{\sigma {T_2}^4}}\] ,
Cancelling A and σ on both sides, we get :
\[\dfrac{1}{9} = \dfrac{{{T_1}^4}}{{{T_2}^4}}\],
Cross multiplication gives,
\[{T_2}^4 = 9{T_1}^4\],
Raising power $\dfrac{1}{4}$ on both sides, we get :
\[{T_2}^{} = {T_1}^{}\sqrt 3 \]
Now, using wien's displacement law :
${\lambda _1}{T_1} = {\lambda _2}{T_2}$,
Substituting the value of T2, we get :
${\lambda _1}{T_1} = {\lambda _2}{T_1}\sqrt 3 $,
Cancelling T1 on both sides :
${\lambda _1} = {\lambda _2}\sqrt 3 $,
$\dfrac{{{\lambda _1}}}{{{\lambda _2}}} = \sqrt 3 $
Therefore the correct answer is option : (D)
Note: Before solving the problem, the student needs to be able to understand the different concepts of Radiation like Stefan’s law, Wien's Displacement law and the terms like total emissive power and spectral emissive power. A common mistake that students make while solving questions involving concepts of radiation is not being able to differentiate between spectral emissive power and total emissive power. While total emissive power is the intensity of radiation emitted by a body, spectral emissive power is the intensity of radiation emitted by a body per unit wavelength.
Complete step by step solution:
The total area under the graph formed between the quantities ${E_\lambda }$ and $\lambda $ denotes total emissive power radiated by a body.
Given that total emissive power at temperature T1 is A,
Using Stefan's law we can say that : $A = e\sigma {T_1}^4$ .
Given that total emissive power at temperature T2 is 9A,
Using Stefan's law we can say that $9A = \sigma {T_2}^4$.
Dividing these two equations, we get :
\[\dfrac{A}{{9A}} = \dfrac{{\sigma {T_1}^4}}{{\sigma {T_2}^4}}\] ,
Cancelling A and σ on both sides, we get :
\[\dfrac{1}{9} = \dfrac{{{T_1}^4}}{{{T_2}^4}}\],
Cross multiplication gives,
\[{T_2}^4 = 9{T_1}^4\],
Raising power $\dfrac{1}{4}$ on both sides, we get :
\[{T_2}^{} = {T_1}^{}\sqrt 3 \]
Now, using wien's displacement law :
${\lambda _1}{T_1} = {\lambda _2}{T_2}$,
Substituting the value of T2, we get :
${\lambda _1}{T_1} = {\lambda _2}{T_1}\sqrt 3 $,
Cancelling T1 on both sides :
${\lambda _1} = {\lambda _2}\sqrt 3 $,
$\dfrac{{{\lambda _1}}}{{{\lambda _2}}} = \sqrt 3 $
Therefore the correct answer is option : (D)
Note: Before solving the problem, the student needs to be able to understand the different concepts of Radiation like Stefan’s law, Wien's Displacement law and the terms like total emissive power and spectral emissive power. A common mistake that students make while solving questions involving concepts of radiation is not being able to differentiate between spectral emissive power and total emissive power. While total emissive power is the intensity of radiation emitted by a body, spectral emissive power is the intensity of radiation emitted by a body per unit wavelength.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE