
The sum of the squares of 2 consecutive odd numbers is 394. Find the numbers.
Answer
619.2k+ views
Hint: Consider the 2 consecutive odd numbers as x and x+2. Find the sum of squares of these numbers.Find the value of x and you will get the two consecutive odd numbers.
“Complete step-by-step answer:”
The sum of the squares of 2 consecutive odd numbers is 394. Let us consider one odd number as x and the other consecutive odd number as (x + 2).
We know the odd numbers 1, 3, 5, 7……
So if one number is ‘x’ then the other consecutive odd number can be found by adding 2 to the \[{{1}^{st}}\]number.
So let us take 2 consecutive odd numbers as x and x + 2.
Now it is given that the sum of squares of these consecutive numbers x and (x + 2) is 394.
\[\therefore {{\left( x \right)}^{2}}+{{\left( x+2 \right)}^{2}}=394\]
We know, \[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\].
Now open the brackets and simplify them,
\[\begin{align}
& {{x}^{2}}+{{x}^{2}}+2\times 2x+{{2}^{2}}=394 \\
& \Rightarrow 2{{x}^{2}}+4x+4=394 \\
\end{align}\]
Divide the entire equation by 2.
\[\begin{align}
& {{x}^{2}}+2x+2=197 \\
& {{x}^{2}}+2x=197-2 \\
& {{x}^{2}}+2x=195 \\
& {{x}^{2}}+2x-195=0-(1) \\
\end{align}\]
We got a quadratic equation which is similar to the general quadratic equation, \[a{{x}^{2}}+bx+c=0\].
By comparing equation (1) and the general equation, we get
a = 1, b = 2, c = -195.
Apply these values in the quadratic formula \[\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\] and find the value of x.
\[\begin{align}
& \dfrac{-2\pm \sqrt{{{\left( 2 \right)}^{2}}-4\times 1\times \left( -195 \right)}}{2\times 1}=\dfrac{-2\pm \sqrt{4+780}}{2} \\
& =\dfrac{-2\pm \sqrt{784}}{2}=\dfrac{-2\pm \sqrt{28\times 28}}{2}=\dfrac{-2\pm 28}{2} \\
\end{align}\]
Hence the roots are \[\left( \dfrac{-2+28}{2} \right)\]and \[\left( \dfrac{-2-28}{2} \right)\]= 13 and -15.
\[\therefore \]Value of x = 13, which is an odd number.
Thus we got the \[{{1}^{st}}\]consecutive number as x =13.
Hence, \[{{2}^{nd}}\]consecutive number as x + 2 = 13 + 2 = 15
Thus the 2 consecutive odd numbers are 13 and 15.
Note: You should consider 2 consecutive terms as x and (x + 2), which is the key to solve this question. We know an odd number, for example 3 is an odd number. (3 + 2) gives 5, which is the odd number near to 3. Thus, 3 and 5 are consecutive terms.
“Complete step-by-step answer:”
The sum of the squares of 2 consecutive odd numbers is 394. Let us consider one odd number as x and the other consecutive odd number as (x + 2).
We know the odd numbers 1, 3, 5, 7……
So if one number is ‘x’ then the other consecutive odd number can be found by adding 2 to the \[{{1}^{st}}\]number.
So let us take 2 consecutive odd numbers as x and x + 2.
Now it is given that the sum of squares of these consecutive numbers x and (x + 2) is 394.
\[\therefore {{\left( x \right)}^{2}}+{{\left( x+2 \right)}^{2}}=394\]
We know, \[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\].
Now open the brackets and simplify them,
\[\begin{align}
& {{x}^{2}}+{{x}^{2}}+2\times 2x+{{2}^{2}}=394 \\
& \Rightarrow 2{{x}^{2}}+4x+4=394 \\
\end{align}\]
Divide the entire equation by 2.
\[\begin{align}
& {{x}^{2}}+2x+2=197 \\
& {{x}^{2}}+2x=197-2 \\
& {{x}^{2}}+2x=195 \\
& {{x}^{2}}+2x-195=0-(1) \\
\end{align}\]
We got a quadratic equation which is similar to the general quadratic equation, \[a{{x}^{2}}+bx+c=0\].
By comparing equation (1) and the general equation, we get
a = 1, b = 2, c = -195.
Apply these values in the quadratic formula \[\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\] and find the value of x.
\[\begin{align}
& \dfrac{-2\pm \sqrt{{{\left( 2 \right)}^{2}}-4\times 1\times \left( -195 \right)}}{2\times 1}=\dfrac{-2\pm \sqrt{4+780}}{2} \\
& =\dfrac{-2\pm \sqrt{784}}{2}=\dfrac{-2\pm \sqrt{28\times 28}}{2}=\dfrac{-2\pm 28}{2} \\
\end{align}\]
Hence the roots are \[\left( \dfrac{-2+28}{2} \right)\]and \[\left( \dfrac{-2-28}{2} \right)\]= 13 and -15.
\[\therefore \]Value of x = 13, which is an odd number.
Thus we got the \[{{1}^{st}}\]consecutive number as x =13.
Hence, \[{{2}^{nd}}\]consecutive number as x + 2 = 13 + 2 = 15
Thus the 2 consecutive odd numbers are 13 and 15.
Note: You should consider 2 consecutive terms as x and (x + 2), which is the key to solve this question. We know an odd number, for example 3 is an odd number. (3 + 2) gives 5, which is the odd number near to 3. Thus, 3 and 5 are consecutive terms.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

