Answer
Verified
441.3k+ views
Hint: Write down the given and the formulas of the for the surface area of the sphere and the curved surface area of a cone. Substitute the values of the given measurements and equate them, and solve the linear equation to get the value of the asked variable.
Complete step-by-step solution:
Curved surface area of a cone with radius $120cm$ and height $160cm$ is given as
Let us consider the radius of the sphere to be \[r\].
Given,
Base of the cone \[ = 120cm\]
Base of the cone can also be taken as the radius of the cone because the base of the cone is a circle.
\[ \Rightarrow \]Radius of the cone \[ = R = 120cm\]
Height of the cone \[ = 160cm\]
The surface area of the sphere is the same as the curved surface area of a cone.
\[ \Rightarrow \]The surface area of the sphere \[ = \] the curved surface area of a cone.
The surface area of a sphere \[ = 4\pi {r^2}\]
The curved surface area of a cone \[ = \pi Rl\]
Here, \[l\] is the length of the cone. Because the length is unknown, we write it in terms of the given values, i.e., in terms of radius and height of the cone.
Since the cone is in the shape of the triangle observed in a two-dimension, we draw a perpendicular through the middle of the cone. When it becomes a right-angled triangle in a two-dimensional plane, we can get the length of the cone using Pythagoras theorem. We have,
\[l = \sqrt {{R^2} + {h^2}} \]
Substituting the value in the formula of the curved surface area of a cone, we get;
The curved surface area of a cone\[ = \pi R\sqrt {{R^2} + {h^2}} \]
Given,
\[4\pi {r^2} = \pi R\sqrt {{R^2} + {h^2}} \]
Substituting the values of the variables from the given question, we get;
\[4\pi {r^2} = \pi \times 120\sqrt {{{\left( {120} \right)}^2} + {{\left( {160} \right)}^2}} \]
Cancelling out the common terms, that is, pi, and simplifying the right-hand side, we get;
\[4{r^2} = 120\sqrt {14400 + 25600} \]
Simplifying the equation, we get;
\[{r^2} = 30\sqrt {40000} \]
Taking the perfect square out, we get;
\[ \Rightarrow {r^2} = 30 \times 200\]
Multiplying the right-hand side, we get;
\[ \Rightarrow {r^2} = 6000\]
Applying square root on both the sides, we get;
\[r = \sqrt {6000} \]
Simplifying the square root, we get;
\[r = 77.45\]
The radius of the sphere is 77.45.
Note: A sphere is defined as the geometrical object which is only in a three- dimensional space. It resembles that of a ball and when viewed in two-dimensional resembles a circle. A cone as well, is a three- dimensional shape in geometry that tapers smoothly from a flat base of a circle into a cone.
Complete step-by-step solution:
Curved surface area of a cone with radius $120cm$ and height $160cm$ is given as
Let us consider the radius of the sphere to be \[r\].
Given,
Base of the cone \[ = 120cm\]
Base of the cone can also be taken as the radius of the cone because the base of the cone is a circle.
\[ \Rightarrow \]Radius of the cone \[ = R = 120cm\]
Height of the cone \[ = 160cm\]
The surface area of the sphere is the same as the curved surface area of a cone.
\[ \Rightarrow \]The surface area of the sphere \[ = \] the curved surface area of a cone.
The surface area of a sphere \[ = 4\pi {r^2}\]
The curved surface area of a cone \[ = \pi Rl\]
Here, \[l\] is the length of the cone. Because the length is unknown, we write it in terms of the given values, i.e., in terms of radius and height of the cone.
Since the cone is in the shape of the triangle observed in a two-dimension, we draw a perpendicular through the middle of the cone. When it becomes a right-angled triangle in a two-dimensional plane, we can get the length of the cone using Pythagoras theorem. We have,
\[l = \sqrt {{R^2} + {h^2}} \]
Substituting the value in the formula of the curved surface area of a cone, we get;
The curved surface area of a cone\[ = \pi R\sqrt {{R^2} + {h^2}} \]
Given,
\[4\pi {r^2} = \pi R\sqrt {{R^2} + {h^2}} \]
Substituting the values of the variables from the given question, we get;
\[4\pi {r^2} = \pi \times 120\sqrt {{{\left( {120} \right)}^2} + {{\left( {160} \right)}^2}} \]
Cancelling out the common terms, that is, pi, and simplifying the right-hand side, we get;
\[4{r^2} = 120\sqrt {14400 + 25600} \]
Simplifying the equation, we get;
\[{r^2} = 30\sqrt {40000} \]
Taking the perfect square out, we get;
\[ \Rightarrow {r^2} = 30 \times 200\]
Multiplying the right-hand side, we get;
\[ \Rightarrow {r^2} = 6000\]
Applying square root on both the sides, we get;
\[r = \sqrt {6000} \]
Simplifying the square root, we get;
\[r = 77.45\]
The radius of the sphere is 77.45.
Note: A sphere is defined as the geometrical object which is only in a three- dimensional space. It resembles that of a ball and when viewed in two-dimensional resembles a circle. A cone as well, is a three- dimensional shape in geometry that tapers smoothly from a flat base of a circle into a cone.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If x be real then the maximum value of 5 + 4x 4x2 will class 10 maths JEE_Main
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE
Give 10 examples for herbs , shrubs , climbers , creepers