Answer
421.5k+ views
Hint: We will find the unit of molar susceptibility from the expression to find molar susceptibility. We will assign the units for the parameters in the expression and finally deduce the unit by cancellation of similar units. We must keep in mind that volume susceptibility is a unit less quantity.
Formula used: \[{{\chi }_{m}}=\dfrac{M{{\chi }_{v}}}{\rho }\]
Complete answer:
Firstly we must understand molar susceptibility. Molar susceptibility is a measure of magnetic susceptibility which is given as the ratio of product of molar mass \[M\] and volume susceptibility \[{{\chi }_{v}}\] to density \[\rho \]of the material.
Molar mass \[M\] is measured in \[kg/mol\]
Now, volume susceptibility \[{{\chi }_{v}}\], is a dimensionless proportionality constant that indicates the degree of magnetization of a material in response to the magnetic field. It is determined by the formula,
\[\begin{align}
& M={{\chi }_{v}}H \\
& {{\chi }_{v}}=\dfrac{M}{H} \\
\end{align}\]
Where, \[M\] is the magnetization of the material which is measured in \[A/m\] and \[H\] is the magnetic field strength which is also measured in \[A/m\].
Therefore, we can understand that volume susceptibility \[{{\chi }_{v}}\] is a dimensionless quantity.
Then, \[\rho \] is the density of the given material which has the usual unit of \[kg/{{m}^{3}}\].
If we substitute all these units to the expression of molar susceptibility,
\[\begin{align}
& {{\chi }_{m}}=\dfrac{M{{\chi }_{v}}}{\rho } \\
& \Rightarrow {{\chi }_{m}}=\dfrac{\dfrac{kg}{mol}}{\dfrac{kg}{{{m}^{3}}}}={{m}^{3}}/mol \\
\end{align}\]
So we got the unit of molar susceptibility as \[{{m}^{3}}/mol\] but it is actually represented as \[{{m}^{3}}\].
Therefore the correct answer is option c.
Note: Molar magnetic susceptibility is also used to classify between paramagnetic and diamagnetic materials. We must always keep in mind that volume susceptibility is a dimensionless quantity. Susceptibility can also be measured as mass susceptibility which has the unit of \[{{m}^{3}}/kg\].
Formula used: \[{{\chi }_{m}}=\dfrac{M{{\chi }_{v}}}{\rho }\]
Complete answer:
Firstly we must understand molar susceptibility. Molar susceptibility is a measure of magnetic susceptibility which is given as the ratio of product of molar mass \[M\] and volume susceptibility \[{{\chi }_{v}}\] to density \[\rho \]of the material.
Molar mass \[M\] is measured in \[kg/mol\]
Now, volume susceptibility \[{{\chi }_{v}}\], is a dimensionless proportionality constant that indicates the degree of magnetization of a material in response to the magnetic field. It is determined by the formula,
\[\begin{align}
& M={{\chi }_{v}}H \\
& {{\chi }_{v}}=\dfrac{M}{H} \\
\end{align}\]
Where, \[M\] is the magnetization of the material which is measured in \[A/m\] and \[H\] is the magnetic field strength which is also measured in \[A/m\].
Therefore, we can understand that volume susceptibility \[{{\chi }_{v}}\] is a dimensionless quantity.
Then, \[\rho \] is the density of the given material which has the usual unit of \[kg/{{m}^{3}}\].
If we substitute all these units to the expression of molar susceptibility,
\[\begin{align}
& {{\chi }_{m}}=\dfrac{M{{\chi }_{v}}}{\rho } \\
& \Rightarrow {{\chi }_{m}}=\dfrac{\dfrac{kg}{mol}}{\dfrac{kg}{{{m}^{3}}}}={{m}^{3}}/mol \\
\end{align}\]
So we got the unit of molar susceptibility as \[{{m}^{3}}/mol\] but it is actually represented as \[{{m}^{3}}\].
Therefore the correct answer is option c.
Note: Molar magnetic susceptibility is also used to classify between paramagnetic and diamagnetic materials. We must always keep in mind that volume susceptibility is a dimensionless quantity. Susceptibility can also be measured as mass susceptibility which has the unit of \[{{m}^{3}}/kg\].
Recently Updated Pages
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x1x2xn be in an AP of x1 + x4 + x9 + x11 + x20-class-11-maths-CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Select the word that is correctly spelled a Twelveth class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)