
The vibrations of four air columns are represented in the figure. The ratio of frequencies np : nq : nr : ns is
A. 12 : 6 : 3 : 5
B. 1 : 2 : 4 : 3
C. 4 : 2 : 3 : 1
D. 6 : 2 : 3 : 4



Answer
483k+ views
Hint: In the case of the closed end air column, the wavelength to be considered will be 4 times the length of the column, whereas, in the case of the open end air column, the wavelength to be considered will be 2 times the length of the column, while calculating the frequencies.
Formula used:
\[n=\dfrac{v}{4l}\]
\[n=\dfrac{v}{2l}\]
Complete step by step answer:
The air column p represents the fundamental closed end.
Thus the frequency of the air column p is given as,
\[{{n}_{p}}=\dfrac{v}{4l}\]
The air column q represents the fundamental open end.
Thus the frequency of the air column q is given as,
\[{{n}_{q}}=\dfrac{v}{2l}\]
The air column r represents the second overtone open end.
Thus the frequency of the air column r is given as,
\[\begin{align}
& {{n}_{r}}=\dfrac{2v}{2l} \\
& {{n}_{r}}=\dfrac{v}{l} \\
\end{align}\]
The air column s represents the second overtone closed end.
Thus the frequency of the air column s is given as,
\[{{n}_{s}}=\dfrac{3v}{4l}\]
The ratio of the frequencies of the air columns p, q, r and s is given as follows:
\[{{n}_{p}}:{{n}_{q}}:{{n}_{r}}:{{n}_{s}}=\dfrac{1}{4}:\dfrac{1}{2}:1:\dfrac{3}{4}\]
Multiply by 4 to take the LCM.
Therefore, the ratio of the frequencies is,
\[{{n}_{p}}:{{n}_{q}}:{{n}_{r}}:{{n}_{s}}=1:2:4:3\]
As, the ratio of frequencies np : nq : nr : ns of four air columns is 1 : 2 : 4 : 3, thus option (B) 1 : 2 : 4 : 3 is correct.
Note:
The things to be on your finger-tips for further information on solving these types of problems are: The frequencies should be calculated considering open end and the closed end concepts.
Formula used:
\[n=\dfrac{v}{4l}\]
\[n=\dfrac{v}{2l}\]
Complete step by step answer:
The air column p represents the fundamental closed end.
Thus the frequency of the air column p is given as,
\[{{n}_{p}}=\dfrac{v}{4l}\]
The air column q represents the fundamental open end.
Thus the frequency of the air column q is given as,
\[{{n}_{q}}=\dfrac{v}{2l}\]
The air column r represents the second overtone open end.
Thus the frequency of the air column r is given as,
\[\begin{align}
& {{n}_{r}}=\dfrac{2v}{2l} \\
& {{n}_{r}}=\dfrac{v}{l} \\
\end{align}\]
The air column s represents the second overtone closed end.
Thus the frequency of the air column s is given as,
\[{{n}_{s}}=\dfrac{3v}{4l}\]
The ratio of the frequencies of the air columns p, q, r and s is given as follows:
\[{{n}_{p}}:{{n}_{q}}:{{n}_{r}}:{{n}_{s}}=\dfrac{1}{4}:\dfrac{1}{2}:1:\dfrac{3}{4}\]
Multiply by 4 to take the LCM.
Therefore, the ratio of the frequencies is,
\[{{n}_{p}}:{{n}_{q}}:{{n}_{r}}:{{n}_{s}}=1:2:4:3\]
As, the ratio of frequencies np : nq : nr : ns of four air columns is 1 : 2 : 4 : 3, thus option (B) 1 : 2 : 4 : 3 is correct.
Note:
The things to be on your finger-tips for further information on solving these types of problems are: The frequencies should be calculated considering open end and the closed end concepts.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
Why was the Vernacular Press Act passed by British class 11 social science CBSE

Arrange Water ethanol and phenol in increasing order class 11 chemistry CBSE

Name the nuclear plant located in Uttar Pradesh class 11 social science CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

How did silk routes link the world Explain with three class 11 social science CBSE
