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Hint- In this question it is given that the captain always remains the same after selecting players. So we will form a new team with remaining players by using the simple concept of combination. Use the basic formula for selecting n number of items from a set of m items for solving the problem.
Complete step-by-step answer:
Given that: in college there are 12 volleyball players including captain, we have to select 9 players out of 12 but it is given that captain remains the same.
As the position of captain is fixed
Now we have to select only 8 volleyball players out of 11 players.
We know that when we have to select “m” items from given “n” total numbers of things, it can be selected in ${}^n{C_m}$ ways.
So, total number of ways of selection of 8 players out of 11 players is:
$ = {}^{11}{C_8}$
Also we know the formulas for combination:
${}^x{C_y} = {}^x{C_{x - y}}$
So simplifying above term, using the given formula we get:
No of ways of selection is:
$
= {}^{11}{C_8} \\
= {}^{11}{C_{11 - 8}} \\
= {}^{11}{C_3} \\
$
Let us further simplify the term
\[
\Rightarrow {}^{11}{C_3} = \dfrac{{11!}}{{3!\left( {11 - 3} \right)!}}{\text{ }}\left[ {\because {}^x{C_y} = \dfrac{{x!}}{{y!\left( {x - y} \right)!}}} \right] \\
= \dfrac{{11!}}{{3!8!}} \\
= \dfrac{{9 \times 10 \times 11}}{{3 \times 2 \times 1}} \\
= \dfrac{{990}}{6} \\
= 165 \\
\]
Therefore, there are 165 ways in which the team can be formed.
Hence, the correct answer is option D.
Note- The method of permutation and combination is used for solving such practical problems. Permutation and combination are the ways to represent a group of objects by selecting them in a set and forming subsets. It defines the various ways to arrange a certain group of data. When we select the data or objects from a certain group it is said to be permutations whereas the order in which they are represented is called combination. Both concepts are very important in Mathematics.
Complete step-by-step answer:
Given that: in college there are 12 volleyball players including captain, we have to select 9 players out of 12 but it is given that captain remains the same.
As the position of captain is fixed
Now we have to select only 8 volleyball players out of 11 players.
We know that when we have to select “m” items from given “n” total numbers of things, it can be selected in ${}^n{C_m}$ ways.
So, total number of ways of selection of 8 players out of 11 players is:
$ = {}^{11}{C_8}$
Also we know the formulas for combination:
${}^x{C_y} = {}^x{C_{x - y}}$
So simplifying above term, using the given formula we get:
No of ways of selection is:
$
= {}^{11}{C_8} \\
= {}^{11}{C_{11 - 8}} \\
= {}^{11}{C_3} \\
$
Let us further simplify the term
\[
\Rightarrow {}^{11}{C_3} = \dfrac{{11!}}{{3!\left( {11 - 3} \right)!}}{\text{ }}\left[ {\because {}^x{C_y} = \dfrac{{x!}}{{y!\left( {x - y} \right)!}}} \right] \\
= \dfrac{{11!}}{{3!8!}} \\
= \dfrac{{9 \times 10 \times 11}}{{3 \times 2 \times 1}} \\
= \dfrac{{990}}{6} \\
= 165 \\
\]
Therefore, there are 165 ways in which the team can be formed.
Hence, the correct answer is option D.
Note- The method of permutation and combination is used for solving such practical problems. Permutation and combination are the ways to represent a group of objects by selecting them in a set and forming subsets. It defines the various ways to arrange a certain group of data. When we select the data or objects from a certain group it is said to be permutations whereas the order in which they are represented is called combination. Both concepts are very important in Mathematics.
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