
Two numbers are in the ratio of 2:5. If they differ by 15, find the numbers.
$
{\text{A}}{\text{. 25 and 10}} \\
{\text{B}}{\text{. }} - {\text{25 and 10}} \\
{\text{C}}{\text{. }}\dfrac{1}{{25}}{\text{ and }}\dfrac{1}{{10}} \\
{\text{D}}{\text{. None of the above }} \\
$
Answer
620.7k+ views
Hint- Here, we will proceed by assuming the two numbers as x and y and then according to the problem statements we will obtain two equations which will be solved by using the substitution method.
“Complete step-by-step answer:”
Let the two numbers be x and y where x is the smaller number and y is the larger number.
Given the difference between the two numbers is 15 i.e., $
y - x = 15 \\
\Rightarrow y = 15 + x{\text{ }} \to {\text{(1)}} \\
$
Also, the ratio of these two numbers is 2:5 i.e., $\dfrac{x}{y} = \dfrac{2}{5}$
By cross multiplying the above equation, we get
$5x = 2y{\text{ }} \to {\text{(2)}}$
Putting the value of y from equation (1), equation (2) becomes
Put x=10 in equation (1), the value of y is given by
So, the assumed two numbers are 10 and 25.
Hence, option A is correct.
Note- In this particular problem, we have developed two equations in two variables which can be easily solved by substitution method (used in the above solution) or elimination method (in this method we make the coefficient of all the variables same except one variable whose value will be eventually calculated by performing algebra to the given equation).
“Complete step-by-step answer:”
Let the two numbers be x and y where x is the smaller number and y is the larger number.
Given the difference between the two numbers is 15 i.e., $
y - x = 15 \\
\Rightarrow y = 15 + x{\text{ }} \to {\text{(1)}} \\
$
Also, the ratio of these two numbers is 2:5 i.e., $\dfrac{x}{y} = \dfrac{2}{5}$
By cross multiplying the above equation, we get
$5x = 2y{\text{ }} \to {\text{(2)}}$
Putting the value of y from equation (1), equation (2) becomes
Put x=10 in equation (1), the value of y is given by
So, the assumed two numbers are 10 and 25.
Hence, option A is correct.
Note- In this particular problem, we have developed two equations in two variables which can be easily solved by substitution method (used in the above solution) or elimination method (in this method we make the coefficient of all the variables same except one variable whose value will be eventually calculated by performing algebra to the given equation).
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

