![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
How do you use transformation to graph the cosine function and determine the amplitude and period of \[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\] ?
Answer
429.3k+ views
Hint: Here in this question, we have to find the period, amplitude and graph of given sine function. Use the form \[a\cos \left( {bx - c} \right) + d\] to Find the amplitude = \[\left| a \right|\] , then Find the period using the formula \[\dfrac{{2\pi }}{{\left| b \right|}}\] and draw a sketch or graph for the co-ordinates \[\left( {x,y} \right)\] by the giving the \[x\] value as 0, 1, 2, 3… we can easily find the value of y by using the given expression.
Complete step-by-step answer:
Let's use the form of the equation i.e., \[a\cos \left( {bx - c} \right) + d\] to find the variables used to find the amplitude, and period.
Now consider the given expression \[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\]
Where,
\[a = - 1\]
\[b = 1\]
\[c = \dfrac{\pi }{4}\]
\[d = 0\]
The Amplitude is the height from the centre line to the peak (or to the trough). Or we can measure the height from highest to lowest points and divide that by 2.
To Find the amplitude = \[\left| a \right|\] .
\[ \Rightarrow \,\,\] Amplitude \[ = \left| a \right| = \left| { - 1} \right| = 1\]
Period is the complete revolution of a wave completing crest and followed by trough.
Otherwise
The Period goes from one peak to the next (or from any point to the next matching point):
Find the period using the formula \[\dfrac{{2\pi }}{{\left| b \right|}}\]
\[ \Rightarrow \,\,\] Period \[ = \dfrac{{2\pi }}{{\left| b \right|}} = \dfrac{{2\pi }}{{\left| 1 \right|}}\, = 2\pi \]
Sketch or graph we can draw by using the coordinates
For coordinates, giving the x values 0, 1, 2, 3… simultaneously to the given equation to get the values of y
The sketch of the given function \[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\] is:
Note: The period is the length of the smallest interval that contains exactly one copy of the repeating pattern. The Amplitude is the height from the centre line to the peak. We use the form of equation i.e., \[a\sin \left( {bx - c} \right) + d\] and we have formula for the period and amplitude and hence we determine the values.
Complete step-by-step answer:
Let's use the form of the equation i.e., \[a\cos \left( {bx - c} \right) + d\] to find the variables used to find the amplitude, and period.
Now consider the given expression \[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\]
Where,
\[a = - 1\]
\[b = 1\]
\[c = \dfrac{\pi }{4}\]
\[d = 0\]
The Amplitude is the height from the centre line to the peak (or to the trough). Or we can measure the height from highest to lowest points and divide that by 2.
To Find the amplitude = \[\left| a \right|\] .
\[ \Rightarrow \,\,\] Amplitude \[ = \left| a \right| = \left| { - 1} \right| = 1\]
Period is the complete revolution of a wave completing crest and followed by trough.
Otherwise
The Period goes from one peak to the next (or from any point to the next matching point):
Find the period using the formula \[\dfrac{{2\pi }}{{\left| b \right|}}\]
\[ \Rightarrow \,\,\] Period \[ = \dfrac{{2\pi }}{{\left| b \right|}} = \dfrac{{2\pi }}{{\left| 1 \right|}}\, = 2\pi \]
Sketch or graph we can draw by using the coordinates
For coordinates, giving the x values 0, 1, 2, 3… simultaneously to the given equation to get the values of y
\[x\] | \[\dfrac{\pi }{4}\] | \[\dfrac{{3\pi }}{4}\] | \[\dfrac{{5\pi }}{4}\] | \[\dfrac{{7\pi }}{4}\] | \[\dfrac{{9\pi }}{4}\] |
\[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\] | \[ - 1\] | \[0\] | \[1\] | \[0\] | \[ - 1\] |
\[\left( {x,y} \right)\] | \[\left( {\dfrac{\pi }{4}, - 1} \right)\] | \[\left( {\dfrac{{3\pi }}{4},0} \right)\] | \[\left( {\dfrac{{5\pi }}{4},1} \right)\] | \[\left( {\dfrac{{7\pi }}{4},0} \right)\] | \[\left( {\dfrac{{9\pi }}{4}, - 1} \right)\] |
The sketch of the given function \[y = - \cos \left( {x - \dfrac{\pi }{4}} \right)\] is:
![seo images](https://www.vedantu.com/question-sets/13ed26fb-9e52-4a73-9381-6ff9bd7260a75135842888641755548.png)
Note: The period is the length of the smallest interval that contains exactly one copy of the repeating pattern. The Amplitude is the height from the centre line to the peak. We use the form of equation i.e., \[a\sin \left( {bx - c} \right) + d\] and we have formula for the period and amplitude and hence we determine the values.
Recently Updated Pages
Master Class 12 Chemistry: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Class 12 Question and Answer - Your Ultimate Solutions Guide
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Master Class 12 Economics: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Master Class 12 Maths: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Master Class 12 Biology: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Master Class 12 Physics: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How many valence electrons does nitrogen have class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)