
What is the name of the compound $Ca{{I}_{2}}$ ?
Answer
516.6k+ views
Hint: While writing the IUPAC name of the compounds, involving two atoms, in which one atom loses the electron and other atom gains that electrons , suffix ide is added at the end of the anion name. Now you can easily write the name of the compound.
Complete answer:
The IUPAC stands for the International Union of Pure and Applied Chemistry and it is the method that is used for the naming of the organic or inorganic compounds and the compounds are known by their IUPAC naming all over.
In the IUPAC naming of those compounds in which one atom of compound loses and the other atom of compound gains the electron , then the suffix ide is added at the end of anion name in the IUPAC name and cation name is written first followed by the name of the anion.
In the given compound $Ca{{I}_{2}}$ , Ca atom can lose maximum of 2 electrons from its valence shell to attain the stable electronic configuration ion its valence shell and thus exhibits +2 oxidation state in most of their compounds and so, its valency is +2. On the other hand, I have a tendency to gain one electron to complete its octet and thus, exhibits -1 oxidation state in their compounds and so, its valency is -1.
Thus, the IUPAC naming of the compound comes out to be calcium iodide or we can write it as Calcium(II) iodide.
Note:
While writing the IUPAC name of the long carbon chain compound, we will first identify the longest carbon chain and we will start numbering from that carbon from which the attached substituent is nearest and while writing the name that name of substituent will be written first which comes first in the alphabetic order along with the carbon number and then add ane, ene or yne if there is -C-C , -C=C or carbon triple bond carbon respectively.
Complete answer:
The IUPAC stands for the International Union of Pure and Applied Chemistry and it is the method that is used for the naming of the organic or inorganic compounds and the compounds are known by their IUPAC naming all over.
In the IUPAC naming of those compounds in which one atom of compound loses and the other atom of compound gains the electron , then the suffix ide is added at the end of anion name in the IUPAC name and cation name is written first followed by the name of the anion.
In the given compound $Ca{{I}_{2}}$ , Ca atom can lose maximum of 2 electrons from its valence shell to attain the stable electronic configuration ion its valence shell and thus exhibits +2 oxidation state in most of their compounds and so, its valency is +2. On the other hand, I have a tendency to gain one electron to complete its octet and thus, exhibits -1 oxidation state in their compounds and so, its valency is -1.
Thus, the IUPAC naming of the compound comes out to be calcium iodide or we can write it as Calcium(II) iodide.
Note:
While writing the IUPAC name of the long carbon chain compound, we will first identify the longest carbon chain and we will start numbering from that carbon from which the attached substituent is nearest and while writing the name that name of substituent will be written first which comes first in the alphabetic order along with the carbon number and then add ane, ene or yne if there is -C-C , -C=C or carbon triple bond carbon respectively.
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