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What is the temperature in vacuum ?

Answer
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Hint:To solve the given question we will learn what does vacuum and temperature mean and then we will proceed to answer the question.A vacuum is a small area of space in which nothing exists. A vacuum is a room that has no objects in it.

Complete answer:
The temperature in a vacuum must be zero by definition. However, according to the third law of thermodynamics, no temperature can be zero. As a result, it is possible to conclude that there is no perfect vacuum, and that if there were, the temperature would be zero.

The average kinetic energy of localised particles is defined as temperature (i.e., the particles surrounding your thermometer). Your temperature reading would be absolute zero if there were no particle’s surrounding your thermometer (because you are in a perfect vacuum).However, we know from the third law of thermodynamics that zero Kelvin cannot be reached, ruling out the possibility of a perfect vacuum.

However, in high vacuums, the concept of temperature begins to break down, so it's not quite as straightforward as that. Thermodynamic temperature is a statistic that can only be described meaningfully in the thermodynamic limit (i.e., assumes many particles are present). Since a vacuum is a rarefied gas with a very low particle density, the statement of the thermodynamic limit is invalid.

A conventional thermometer should not be used to calculate the temperature in a vacuum for this (and many other reasons). This may, however, be accomplished with a laser thermometer, which is how we normally measure temperatures in space. In other words, the temperature of a perfect vacuum will be zero degrees Fahrenheit. Since this is not realistic, the temperature must be very low (in space the temperature is $\approx 27K$).

Note:One must understand what room temperature is and what its value is; room temperature is the usual range of temperature in which humans feel relaxed habitation, and its value is most commonly taken as $300K\left( 27^{\circ}C\text{ }or\text{ }80\text{ }F \right)$.