Question

Which of the following is a most polar bond?
 $ \begin{array}{*{20}{l}}
  {A.{\text{ }}Cl{\text{ }} - {\text{ }}Cl} \\
  {B.{\text{ }}N{\text{ }} - F} \\
  {C.{\text{ }}C{\text{ }} - {\text{ }}F} \\
  {D.{\text{ }}O{\text{ }} - F}
\end{array} $

Answer 1

Hint :A polar covalent bond exists when atoms with different electronegativities share electrons in a covalent bond. Higher the difference in the electronegativities of the atom, higher will be the polarity of the bond.

Complete Step By Step Answer:
The carbon atom and fluorine atoms are stated to be joined with the aid of a covalent bond. The cause that the two atoms stick collectively is that the shared pair of electrons is drawn to the nucleus of both. There is a large difference in the electronegative of both atoms. Therefore, $ C - F $ is the maximum polar bond.
It bureaucracy from hydrogen atoms, every with one electron in a 1s orbital. Each hydrogen atom shares the 2 electrons inside the covalent bond, and everyone acquires a helium-like electron configuration. The two atoms in the molecule are joined with the aid of a shared pair of electrons.
 $ Cl{\text{ }} - {\text{ }}Cl $ has a nonpolar bond because electronegative of both the compounds are the same. Hydrogen is likewise much less electronegative than the not unusual nonmetals. Consequently, while a hydrogen atom is bonded to non unusual nonmetals, the ensuing polar bond has a partial advantageous rate on the hydrogen atom.
While nitrogen, oxygen and chlorine do not have large differences in their electronegative hence they don’t have much polar bond compared to $ C - F $ molecules.
Hence option C is the correct answer.

Note :
The bond between hydrogen and chlorine in $ HCl $ is a polar covalent bond. It's far shaped with the aid of sharing an electron pair between the 2 atoms. Given that chlorine is more electronegative than hydrogen, it pulls the shared electron pair more strongly toward itself, for this reason acquiring a partial terrible rate while hydrogen acquires a partial wonderful fee. For this reason, the bond is polar in nature.