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Which of the following is a positive overlap which leads to bonding?
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Answer
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Hint: As we know that when orbitals are present in the same phase, they overlap with each other resulting in bond formation which is called positive overlap, when two orbitals of different phases overlap they result in negative overlap and when orbitals do not overlap with each other they result in zero overlap.

Complete answer:
As we know that p-orbital possess a dumbbell shaped orbitals where one of the lobe is positively spin and the other lobe is negative spin and we also know that when two orbitals containing same spin will overlap with each other, they will result in a positive overlap and when the two orbitals containing two different spins overlap, they will result in a negative overlap.

Now, let us talk about each given option one by one. We can see that in the first option, there are two different orbitals that are one p-orbital and one s-orbital possessing positive and negative spins. Thus, it will have a zero overlap where no bonding between these two will not take place.
Similarly, in the second and fourth option we can see the negative overlap where positive spin and negative spin containing orbitals are overlapping with each other and therefore both of these options are also incorrect.

Now, the third option contains two ${p_x}$ orbitals and they are showing positive and negative spin and as they both are containing similar spin, they will thus form a positive overlap resulting in a bonding molecular orbital. Hence, this is the correct option.

Therefore, from the above explanation we can say that the correct answer is (C).

Note: Always remember that positive overlap will be the result of two similar spins and negative overlap is always shown by two opposite spins. Also, the orbital which is formed by the positive overlap is called a bonding molecular orbital and the orbital which is formed by negative overlap is an antibonding molecular orbital.