Answer
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Hint: The aromatic compounds are those which have one more ring in its structure and it contains pi electrons which are delocalized all over the structure. Also, the aromaticity of a compound can be found with the help of Huckel’s rule. According to which a compound which contains \[\left( {4n + 2} \right)\] pi electrons is considered in nature. Thus we will analyze each compound.
Formula Used:
For aromatic compounds, the number of pi electrons must be \[\left( {4n + 2} \right)\], where n is an integer starting from zero.
Complete Answer:
Aromatic compounds are those compounds that contain one more ring and follow the Huckel rule of aromaticity. According to the Huckel rule of aromaticity, a planar ring molecule will be aromatic in nature when it contains a number of pi electrons in order of \[\left( {4n + 2} \right)\]. We will analyze each compound respectively. Each double bond constitutes two electrons and a negative charge also indicates two electrons.
Here the total number of electrons are \[\left( {2 + 2 = 4} \right)\]. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Total number pi bond is one and it has a negative charge also which in total has \[\left( {2 + 2 = 4} \right)\] electrons. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Total number of pi bonds is four and it has a negative charge also. Therefore the total number of electrons is: \[n = 2\] which is in the order of \[\left( {4n + 2} \right)\] for \[n = 2\]. Hence it is an aromatic compound.
Here the total number of electrons are \[\left( {2 + 2 = 4} \right)\]. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Hence the correct option is C.
Note:
It must be noted that each pi bond constitutes two electrons and a negative charge accounts for two electrons where a positive charge does not account for any electron. This is because a negative charge is developed when atoms accept electrons and a positive charge is developed when atoms lose electrons. Also for aromatic compounds, the compound must be planar.
Formula Used:
For aromatic compounds, the number of pi electrons must be \[\left( {4n + 2} \right)\], where n is an integer starting from zero.
Complete Answer:
Aromatic compounds are those compounds that contain one more ring and follow the Huckel rule of aromaticity. According to the Huckel rule of aromaticity, a planar ring molecule will be aromatic in nature when it contains a number of pi electrons in order of \[\left( {4n + 2} \right)\]. We will analyze each compound respectively. Each double bond constitutes two electrons and a negative charge also indicates two electrons.
Here the total number of electrons are \[\left( {2 + 2 = 4} \right)\]. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Total number pi bond is one and it has a negative charge also which in total has \[\left( {2 + 2 = 4} \right)\] electrons. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Total number of pi bonds is four and it has a negative charge also. Therefore the total number of electrons is: \[n = 2\] which is in the order of \[\left( {4n + 2} \right)\] for \[n = 2\]. Hence it is an aromatic compound.
Here the total number of electrons are \[\left( {2 + 2 = 4} \right)\]. Thus it is not in order of \[\left( {4n + 2} \right)\], therefore it is not an aromatic compound.
Hence the correct option is C.
Note:
It must be noted that each pi bond constitutes two electrons and a negative charge accounts for two electrons where a positive charge does not account for any electron. This is because a negative charge is developed when atoms accept electrons and a positive charge is developed when atoms lose electrons. Also for aromatic compounds, the compound must be planar.
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